Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 8)
8.
The following resistors (one each) are connected in a series circuit: 470 
, 680 , 1 k, and 1.2 k. The voltage source is 20 V. Current through the 680 resistor is approximately
, 680 , 1 k, and 1.2 k. The voltage source is 20 V. Current through the 680 resistor is approximatelyDiscussion:
23 comments Page 1 of 3.
GOPALAKRISHNAN said:
1 decade ago
How did you calculate. ?
Nagendra said:
1 decade ago
Current flowing will be same through out the circuit..
So total resistors = 470 + 680 + 1k + 1.2K = 3.35 kohms
i=v/r
20/3.35k
=5.97mA
which is equal to 6mA
So total resistors = 470 + 680 + 1k + 1.2K = 3.35 kohms
i=v/r
20/3.35k
=5.97mA
which is equal to 6mA
Rahul said:
1 decade ago
Yes correct.
Ramesh said:
1 decade ago
How it is correct?
Srinuivas said:
1 decade ago
In series current is same ,but voltage dropacross all the resistors are different
here total voltage 20v
r=680 ohms ,470,1200,1000
ohms law v=ir
i=20/3.35k
=5.97milliamps
here total voltage 20v
r=680 ohms ,470,1200,1000
ohms law v=ir
i=20/3.35k
=5.97milliamps
KISHORE said:
1 decade ago
ANSWER C IS CORRECT
Sandeep chandraker said:
1 decade ago
Total resistors = 470 + 680 + 1k + 1.2K = 3.35 kohms
V=20v
V=IR
20=I*3.35
I=20/3.35K
I=5.97mA
which is equal to 6mA
V=20v
V=IR
20=I*3.35
I=20/3.35K
I=5.97mA
which is equal to 6mA
J khandelwal said:
1 decade ago
Because in series current through all resistor are same.
Pushpendra singh said:
1 decade ago
Total resistors =470/1000+680/1000+1+1. 2=3. 35 kohms.
Voltage = 20V.
V=IR.
I=V/R.
=20/3. 35k.
I=5. 97mA.
Voltage = 20V.
V=IR.
I=V/R.
=20/3. 35k.
I=5. 97mA.
Rojalin bhutia said:
1 decade ago
Series current is same, but voltage drop across all the resistors are different.
Here total voltage 20v.
R=680 ohms, 470, 1200, 1000.
Ohms law V=IR.
I = 20/3.35k.
= 5.97 milli amps.
Here total voltage 20v.
R=680 ohms, 470, 1200, 1000.
Ohms law V=IR.
I = 20/3.35k.
= 5.97 milli amps.
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