Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 8)
8.
The following resistors (one each) are connected in a series circuit: 470 
, 680 , 1 k, and 1.2 k. The voltage source is 20 V. Current through the 680 resistor is approximately
, 680 , 1 k, and 1.2 k. The voltage source is 20 V. Current through the 680 resistor is approximatelyDiscussion:
23 comments Page 2 of 3.
Ashwini S said:
9 years ago
But they have asked to find the current across the 680-ohm resistor, then how 6mA will be the answer?
(3)
R.Bairwa said:
1 decade ago
Current will be same in all resistance because of series combination.
(1)
Kunal said:
5 years ago
Tr=470+680+1000+1200.
Tr=3350.
I=v÷r.
I=20÷3350.
I=0.006.
I=6mA.
Tr=3350.
I=v÷r.
I=20÷3350.
I=0.006.
I=6mA.
(3)
J khandelwal said:
1 decade ago
Because in series current through all resistor are same.
Gurav said:
7 years ago
V / K ohm = mili amp is hat true?
Explain, please .
Explain, please .
Anusha said:
1 decade ago
But they asked to calculate current at 680 v right?
Anthony said:
8 years ago
Current in Series Circuit is constant.
(1)
Kiran said:
8 years ago
Friends how to calculate 20/3350?
Prathisha said:
8 years ago
Nice Explanation, Thanks @Amala.
GOPALAKRISHNAN said:
1 decade ago
How did you calculate. ?
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