Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 7)
7.
The total power in a certain circuit is 12 W. Each of the four equal-value series resistors making up the circuit dissipates
Discussion:
18 comments Page 1 of 2.
Ambika prasad said:
8 years ago
Same resistance means R1=R2=R3=R4=R
So the total resistance=R1+R2+R3+R4
=R+R+R+R=4R.
And we know that, 'P' is inversely proportional to R. So 'P' will decrease when increasing 'R'.
P=I^2 * R.
=>P=I^2 * 4R,
=>12/4 = I^2 * R,
=>P = 3 W.
So the total resistance=R1+R2+R3+R4
=R+R+R+R=4R.
And we know that, 'P' is inversely proportional to R. So 'P' will decrease when increasing 'R'.
P=I^2 * R.
=>P=I^2 * 4R,
=>12/4 = I^2 * R,
=>P = 3 W.
(3)
B.Lavanya said:
4 years ago
Total power =12.
W/R = 12w/4R = 3W.
W/R = 12w/4R = 3W.
(2)
Vipin said:
7 years ago
In series connection voltage across each resistors is different.
The Power eqn is p=vi.
So voltage in each resistors is different.
But current is same in series connection.
So, Why not power in each resistors is different?
The Power eqn is p=vi.
So voltage in each resistors is different.
But current is same in series connection.
So, Why not power in each resistors is different?
(2)
Siva said:
1 decade ago
No current remains constant after each resistor in series so p=i^2r. In series approach with current and for parallel go with voltage.
Shakil said:
3 years ago
Good explanation. Thanks.
Harsha said:
8 years ago
In some of the books I have read that the total power in series circuit is equal to
1/ptotal = (1/p1)+(1/p2)+(1/p3).
The power formula is similar to resistors in parallel formula which formula should be applied.
1/ptotal = (1/p1)+(1/p2)+(1/p3).
The power formula is similar to resistors in parallel formula which formula should be applied.
Balu said:
9 years ago
Total power =12 W.
12 = 4P.
P = 3W.
12 = 4P.
P = 3W.
Priyaranjan said:
10 years ago
Powers are additive in series and parallel circuits. Hence correct option is C.
Manoj said:
1 decade ago
If those resistors are in parallel what is the answer?
Mohan said:
1 decade ago
Total power p=12
All equal value resistors so
p= p1=p2=p3=p4
total power p = p+p+p+p
12=4p
p=12/4
p=3 w
All equal value resistors so
p= p1=p2=p3=p4
total power p = p+p+p+p
12=4p
p=12/4
p=3 w
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