Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 7)
7.
The total power in a certain circuit is 12 W. Each of the four equal-value series resistors making up the circuit dissipates
Discussion:
18 comments Page 1 of 2.
Ambika prasad said:
8 years ago
Same resistance means R1=R2=R3=R4=R
So the total resistance=R1+R2+R3+R4
=R+R+R+R=4R.
And we know that, 'P' is inversely proportional to R. So 'P' will decrease when increasing 'R'.
P=I^2 * R.
=>P=I^2 * 4R,
=>12/4 = I^2 * R,
=>P = 3 W.
So the total resistance=R1+R2+R3+R4
=R+R+R+R=4R.
And we know that, 'P' is inversely proportional to R. So 'P' will decrease when increasing 'R'.
P=I^2 * R.
=>P=I^2 * 4R,
=>12/4 = I^2 * R,
=>P = 3 W.
(3)
Akash said:
1 decade ago
Total Power = 12W.
Four Resistors are in series and equal values,
Total Power = P1+P2+P3+P4.
12Watts = 3+3+3+3.
(OR)
So, total power/no of resistors,
12/4 = 3.
So each resistor have 3Watts Because the power in the series circuit also additive.
Four Resistors are in series and equal values,
Total Power = P1+P2+P3+P4.
12Watts = 3+3+3+3.
(OR)
So, total power/no of resistors,
12/4 = 3.
So each resistor have 3Watts Because the power in the series circuit also additive.
Thirumalesh said:
1 decade ago
Total Power (P) = 12 W.
Given that : All four resistor values are equal.
i.e, R1=R2=R3=R4= R (say)
corresponding Power values also equal (P = P1=P2=P3=P4 )
So total power in four equal-value resistors = 4P
Thus
4P = 12
P = 12/4
P = 3 W.
Given that : All four resistor values are equal.
i.e, R1=R2=R3=R4= R (say)
corresponding Power values also equal (P = P1=P2=P3=P4 )
So total power in four equal-value resistors = 4P
Thus
4P = 12
P = 12/4
P = 3 W.
Vipin said:
7 years ago
In series connection voltage across each resistors is different.
The Power eqn is p=vi.
So voltage in each resistors is different.
But current is same in series connection.
So, Why not power in each resistors is different?
The Power eqn is p=vi.
So voltage in each resistors is different.
But current is same in series connection.
So, Why not power in each resistors is different?
(2)
Harsha said:
8 years ago
In some of the books I have read that the total power in series circuit is equal to
1/ptotal = (1/p1)+(1/p2)+(1/p3).
The power formula is similar to resistors in parallel formula which formula should be applied.
1/ptotal = (1/p1)+(1/p2)+(1/p3).
The power formula is similar to resistors in parallel formula which formula should be applied.
Pavithra said:
1 decade ago
The total power is 12. When all the resistors are in series they will dissipate equal power since there is a 4 resistors connected in series the power across each resistor is 4W.
i.e., 12/4=3W.
i.e., 12/4=3W.
Sathiya raj said:
1 decade ago
In series resistance r1=r2=r3=r4.., So total power is divided by no of resisters is to be connected in series.
For example 12 resistors connected means power is 1W.
For example 12 resistors connected means power is 1W.
Mohan said:
1 decade ago
Total power p=12
All equal value resistors so
p= p1=p2=p3=p4
total power p = p+p+p+p
12=4p
p=12/4
p=3 w
All equal value resistors so
p= p1=p2=p3=p4
total power p = p+p+p+p
12=4p
p=12/4
p=3 w
Siva said:
1 decade ago
No current remains constant after each resistor in series so p=i^2r. In series approach with current and for parallel go with voltage.
Priyaranjan said:
10 years ago
Powers are additive in series and parallel circuits. Hence correct option is C.
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