Electrical Engineering - Series Circuits - Discussion

Discussion Forum : Series Circuits - General Questions (Q.No. 7)
7.
The total power in a certain circuit is 12 W. Each of the four equal-value series resistors making up the circuit dissipates
12 W
48 W
3 W
8 W
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
18 comments Page 2 of 2.

Lovepreet said:   1 decade ago
I am not agree because voltage reduced after any resistance.

Akash said:   1 decade ago
Total Power = 12W.

Four Resistors are in series and equal values,

Total Power = P1+P2+P3+P4.
12Watts = 3+3+3+3.

(OR)

So, total power/no of resistors,
12/4 = 3.

So each resistor have 3Watts Because the power in the series circuit also additive.

Thirumalesh said:   1 decade ago
Total Power (P) = 12 W.
Given that : All four resistor values are equal.
i.e, R1=R2=R3=R4= R (say)
corresponding Power values also equal (P = P1=P2=P3=P4 )
So total power in four equal-value resistors = 4P
Thus
4P = 12
P = 12/4
P = 3 W.

Pavithra said:   1 decade ago
The total power is 12. When all the resistors are in series they will dissipate equal power since there is a 4 resistors connected in series the power across each resistor is 4W.

i.e., 12/4=3W.

Sathiya raj said:   1 decade ago
In series resistance r1=r2=r3=r4.., So total power is divided by no of resisters is to be connected in series.

For example 12 resistors connected means power is 1W.

Kishore said:   1 decade ago
In series, four resistors equal power also equal dissipate.

Chintan said:   1 decade ago
Total power=12.

All resister in series.

So, p=12/4.

P=3w.

Anand said:   1 decade ago
Nice Explanation


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