Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 7)
7.
A 6.8 k resistor, a 7 mH coil, and a 0.02 F capacitor are in parallel across a 17 kHz ac source. The coil's internal resistance, RW, is 30 . The equivalent parallel resistance, Rp(eq), is
1,878
18,780
18,750
626
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
34 comments Page 3 of 4.

Mouni said:   1 decade ago
I need some clarity about this question.

Mike said:   1 decade ago
This answer doesn't make any sense. How is the equivalent parallel resistance larger than the one resistor that is known, 6800?

If in parallel, it should be at least lower than 6800.

Rafi said:   1 decade ago
Can any one provide solution in detail? Please.

Souma said:   1 decade ago
I need some quickly make out method, someone please help.

Ajit Kumar said:   1 decade ago
1/(Z-30) = 1/6.8 + J*.017*0.02 + 1/(J17*7).

Now Z can be calculated in form of 1/z = x + j Y.

Rp = 1/x.

Pranoti said:   1 decade ago
I can not understand by this above solution. I want something simple and quickly under stable method. Please provide it.

Mrakovic said:   1 decade ago
Rp(eq) = Rw(Q^2+1).

Q = XL/Rw.

Sunil said:   1 decade ago
It is Resistance that has been asked for not impedance, in which case the answer should have been 29.9ohms.

Sirisha said:   1 decade ago
1/Z=(1/R)+[1/(Rw+jXl)]+[1/jXc].

Is the above equation correct or did go wrong any where, because I got totally different answer. Please help me?

Krystina said:   1 decade ago
I am getting around the same answer as you: 294.2-1174j. Even if you use w = 17 kHz (leaving out the 2*pi) you still dont get it.

I got 34.6+122.4j. Not sure how they are getting this answer.


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