Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 15)
A 24 resistor, an inductor with a reactance of 120 , and a capacitor with a reactance of 120 are in series across a 60 V source. The circuit is at resonance. The voltage across the inductor is
60 V
660 V
30 V
300 V
Answer: Option
No answer description is available. Let's discuss.
10 comments Page 1 of 1.

Vishal said:   1 decade ago
As in resonace impedance equal to resistance
Current = 60/24 = 2.5
Vtg across inductor = 120*2.5 = 300V

Sandy said:   9 years ago
i = v/r.
= 24/60 = 0.4 right.

Mudassar inayat said:   9 years ago
When circuit is at resonance then inductor have effect an circuit the voltage drop across inductor is zero? I think.

Veerababu said:   8 years ago
The circuit is resonance so inductive reactance is equal to capacitive reactance so only resistor active circuit is voltage is 60v.

Imdad said:   7 years ago
Yes, you are right @Veerababu.

Rajat said:   7 years ago
But how can the voltage across inductor is grater than the voltage of battery?

Manju said:   7 years ago
Voltage across inductor becomes +300v at same time voltage across the capacitor becomes -300v so both get cancel each other, and only voltage drop across are. But +300v is present across inductor at any instant, compared over all circuit voltage is 60v for inductor only its 300v.

Fidel said:   5 years ago
Good one, thanks @Manju.

Sankar said:   4 years ago
The voltage across the inductor is Vl = I Xl, that is total current in the circuit multiplied with inductive reactance.

Engr. Kashif aziz said:   4 years ago
Series resonance circuit as VL = -VC the resulting reactive voltages are zero and all the supply voltage is dropped across the resistor. Therefore, VR = V supply and it is for this reason that series resonance circuits are known as voltage resonance circuits. So option A that is 60 v.

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