# Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 15)

15.

A 24 resistor, an inductor with a reactance of 120 , and a capacitor with a reactance of 120 are in series across a 60 V source. The circuit is at resonance. The voltage across the inductor is

Discussion:

10 comments Page 1 of 1.
Engr. Kashif aziz said:
3 years ago

Series resonance circuit as VL = -VC the resulting reactive voltages are zero and all the supply voltage is dropped across the resistor. Therefore, VR = V supply and it is for this reason that series resonance circuits are known as voltage resonance circuits. So option A that is 60 v.

Sankar said:
3 years ago

The voltage across the inductor is Vl = I Xl, that is total current in the circuit multiplied with inductive reactance.

Fidel said:
4 years ago

Good one, thanks @Manju.

Manju said:
5 years ago

Voltage across inductor becomes +300v at same time voltage across the capacitor becomes -300v so both get cancel each other, and only voltage drop across are. But +300v is present across inductor at any instant, compared over all circuit voltage is 60v for inductor only its 300v.

Rajat said:
5 years ago

But how can the voltage across inductor is grater than the voltage of battery?

Imdad said:
6 years ago

Yes, you are right @Veerababu.

Veerababu said:
6 years ago

The circuit is resonance so inductive reactance is equal to capacitive reactance so only resistor active circuit is voltage is 60v.

Mudassar inayat said:
7 years ago

When circuit is at resonance then inductor have effect an circuit the voltage drop across inductor is zero? I think.

Sandy said:
8 years ago

i = v/r.

= 24/60 = 0.4 right.

= 24/60 = 0.4 right.

Vishal said:
1 decade ago

As in resonace impedance equal to resistance

Current = 60/24 = 2.5

Vtg across inductor = 120*2.5 = 300V

Current = 60/24 = 2.5

Vtg across inductor = 120*2.5 = 300V

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