Electrical Engineering - RL Circuits - Discussion

Discussion Forum : RL Circuits - General Questions (Q.No. 5)
5.
A 470 resistor and a coil with 125 inductive reactance are in parallel. Both components are across a 15 V ac voltage source. Current through the inductor is
152 mA
32 mA
12 mA
120 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 2 of 2.

Ratna said:   8 years ago
Since the voltage source is parllel to both resistances.
(1)

Joseph said:   1 decade ago
Current through inductor = 15/125=0.12 = 120 mA.

Sushant said:   1 decade ago
Current through conductor = (152*470)/595.


Post your comments here:

Your comments will be displayed after verification.