Electrical Engineering - RL Circuits - Discussion

Discussion :: RL Circuits - General Questions (Q.No.5)

5. 

A 470 resistor and a coil with 125 inductive reactance are in parallel. Both components are across a 15 V ac voltage source. Current through the inductor is

[A]. 152 mA
[B]. 32 mA
[C]. 12 mA
[D]. 120 mA

Answer: Option D

Explanation:

No answer description available for this question.

Joseph said: (Aug 1, 2011)  
Current through inductor = 15/125=0.12 = 120 mA.

Elavendhan said: (Jan 3, 2012)  
According Ohms law
V = IR
I = v/R
V = 15 v
I = ?
R1 = 470
R2 = 125
Both the Resistance in parallel so,
R = (R1*R2)/(R1+R2)
= (470*125)/(470+125)
= 98.739
I = 15/98.739
Ans = 152 mA

Biswajit Oec said: (Feb 2, 2012)  
After calculate 152MA PUT votage divider rule it is i*R1/R1+R2.

Paban Borah(Assam) said: (Jan 20, 2013)  
R1=470.
R2=125.

Circuit current(i)=152mA.

Current through inductor(i2)=(i*R1)/(R1+R2)=120mA.

Darji Divyang said: (Mar 2, 2014)  
Here circuit current is 152mA but dear friends in question said that find the current through an inductor so that answer is 120mA.

15/125=120mA.

Priyaphilemon said: (Feb 4, 2015)  
In an AC circuit containing pure inductance the following formula applies:

Current through ac inductance = voltage/opposition to current flow.

I = V/XL.
I = 15/125.
I = 0.12a.
I = 120ma.

Vijay Bairoji said: (Aug 23, 2015)  
According Ohms law.

V = IR.
I = v/R.
V = 15 v
I = ?

R1 = 470.
R2 = 125.

Both the Resistance in parallel so,

R = (R1*R2)/(R1+R2).
= (470*125)/(470+125).
= 98.739.

I = 15/98.739.

Answer = 152 mA.

But current through inductor is:

IL= (i*R1)/(R1+R2).

Sushant said: (Sep 11, 2015)  
Current through conductor = (152*470)/595.

Prasanta Bcet said: (Dec 27, 2016)  
Here, we have to find the source current then put current division rule.

Supriyo Kumar said: (Feb 3, 2017)  
Since it is voltage source is parallel to both resistances.
So, In parallel circuit v1=v2=v3=v.
Current in inductor, I = V/R =15/125 = 120 mA.

Ratna said: (Apr 28, 2017)  
Since the voltage source is parllel to both resistances.

Mohsin said: (Jan 18, 2019)  
You can't just simply calculate Req like 2 resistors in parallel, proper impedance have to be calculated for parallel RL circuit.
I = V/Z.
Z= 1/*(1/R)^2+(1/XL)^2.

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