Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 5)
5.
A 470 
resistor and a coil with 125 inductive reactance are in parallel. Both components are across a 15 V ac voltage source. Current through the inductor is
resistor and a coil with 125 inductive reactance are in parallel. Both components are across a 15 V ac voltage source. Current through the inductor isDiscussion:
13 comments Page 2 of 2.
Supriyo kumar said:
9 years ago
Since it is voltage source is parallel to both resistances.
So, In parallel circuit v1=v2=v3=v.
Current in inductor, I = V/R =15/125 = 120 mA.
So, In parallel circuit v1=v2=v3=v.
Current in inductor, I = V/R =15/125 = 120 mA.
Mohsin said:
7 years ago
You can't just simply calculate Req like 2 resistors in parallel, proper impedance have to be calculated for parallel RL circuit.
I = V/Z.
Z= 1/*(1/R)^2+(1/XL)^2.
I = V/Z.
Z= 1/*(1/R)^2+(1/XL)^2.
Javed said:
5 years ago
I = V/R.
I = 12/125 = 0.12,
0.12 * 10^2,
0.12 * 1000 = 120mA.
I = 12/125 = 0.12,
0.12 * 10^2,
0.12 * 1000 = 120mA.
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