# Electrical Engineering - RL Circuits - Discussion

Discussion Forum : RL Circuits - General Questions (Q.No. 2)

2.

The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is

Discussion:

12 comments Page 1 of 2.
ABHINAV KUMAR said:
1 decade ago

In RL circuit both R & L are connected in series. Voltage drop is more at high impedance as V proportional to R whil I constant. So impedance of inductor should be high. Hence frequency should be increases as Zl=wL.

Ganesh shind said:
1 decade ago

For resistive circuit voltage and current are in phase but for.

R-L circuit current lags the voltage by 90 degree so there is phase difference phi because of that in R-L circuit current is out of phase.

R-L circuit current lags the voltage by 90 degree so there is phase difference phi because of that in R-L circuit current is out of phase.

Brundha said:
10 years ago

To make the resistor voltage less than the inductor voltage?

Normally we know the formula for frequency,

xl = 2*3.14*l*f.

So, the voltage across the inductor is increased.

Normally we know the formula for frequency,

xl = 2*3.14*l*f.

So, the voltage across the inductor is increased.

Danish baidar said:
1 decade ago

To make the resistor voltage less than the inductor voltage.

Inductor voltage has to be increased.

VL=I(2*pi*f*L)

So f is Increased to increase Inductor voltage.

Inductor voltage has to be increased.

VL=I(2*pi*f*L)

So f is Increased to increase Inductor voltage.

Kishore said:
1 decade ago

XL= 2*3.14*f*L

Here inductive reactance increases by increasing frequency, so the voltage across the inductor increases.

Here inductive reactance increases by increasing frequency, so the voltage across the inductor increases.

Prasad hajare said:
7 years ago

The frequency increase so the voltage across the inductor also increased. This one right conclusion.

Surendra said:
8 years ago

XL = 2 * &phi * f * L.

The frequency increase so the voltage across the inductor also increased.

The frequency increase so the voltage across the inductor also increased.

Sanu singh said:
9 years ago

But we have to inductive voltage more than resistance voltage so we have to decrease Xl.

Mani said:
1 decade ago

For this the inductor resistance need to reduce and will done when frequency decreases.

Shardul said:
9 years ago

Xl=2*3.14*f*l and Xc=1/2*3.14*f*c. So for in case of indicator its proportional form.

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