Electrical Engineering - RL Circuits - Discussion

Discussion :: RL Circuits - General Questions (Q.No.2)

2. 

The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is

[A]. increased
[B]. decreased
[C]. doubled
[D]. not a factor

Answer: Option A

Explanation:

No answer description available for this question.

Mani said: (Jun 23, 2011)  
For this the inductor resistance need to reduce and will done when frequency decreases.

Abhinav Kumar said: (Nov 13, 2011)  
In RL circuit both R & L are connected in series. Voltage drop is more at high impedance as V proportional to R whil I constant. So impedance of inductor should be high. Hence frequency should be increases as Zl=wL.

Kishore said: (Jan 23, 2012)  
XL= 2*3.14*f*L

Here inductive reactance increases by increasing frequency, so the voltage across the inductor increases.

Danish Baidar said: (Apr 16, 2013)  
To make the resistor voltage less than the inductor voltage.
Inductor voltage has to be increased.

VL=I(2*pi*f*L)

So f is Increased to increase Inductor voltage.

Ganesh Shind said: (Jul 20, 2013)  
For resistive circuit voltage and current are in phase but for.

R-L circuit current lags the voltage by 90 degree so there is phase difference phi because of that in R-L circuit current is out of phase.

Dhiva said: (May 28, 2014)  
Generally is formula Xl=2piFL.

So. frequency is increased.

Brundha said: (Jan 19, 2015)  
To make the resistor voltage less than the inductor voltage?

Normally we know the formula for frequency,

xl = 2*3.14*l*f.

So, the voltage across the inductor is increased.

Shardul said: (Mar 8, 2015)  
Xl=2*3.14*f*l and Xc=1/2*3.14*f*c. So for in case of indicator its proportional form.

Sanu Singh said: (Dec 7, 2015)  
But we have to inductive voltage more than resistance voltage so we have to decrease Xl.

Surendra said: (Sep 9, 2016)  
XL = 2 * &phi * f * L.

The frequency increase so the voltage across the inductor also increased.

Saubhagya said: (Jan 9, 2017)  
I can't get this question. Anyone explain me clearly.

Prasad Hajare said: (Sep 7, 2017)  
The frequency increase so the voltage across the inductor also increased. This one right conclusion.

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