# Electrical Engineering - RL Circuits - Discussion

### Discussion :: RL Circuits - General Questions (Q.No.2)

2.

The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is

 [A]. increased [B]. decreased [C]. doubled [D]. not a factor

Explanation:

No answer description available for this question.

 Mani said: (Jun 23, 2011) For this the inductor resistance need to reduce and will done when frequency decreases.

 Abhinav Kumar said: (Nov 13, 2011) In RL circuit both R & L are connected in series. Voltage drop is more at high impedance as V proportional to R whil I constant. So impedance of inductor should be high. Hence frequency should be increases as Zl=wL.

 Kishore said: (Jan 23, 2012) XL= 2*3.14*f*L Here inductive reactance increases by increasing frequency, so the voltage across the inductor increases.

 Danish Baidar said: (Apr 16, 2013) To make the resistor voltage less than the inductor voltage. Inductor voltage has to be increased. VL=I(2*pi*f*L) So f is Increased to increase Inductor voltage.

 Ganesh Shind said: (Jul 20, 2013) For resistive circuit voltage and current are in phase but for. R-L circuit current lags the voltage by 90 degree so there is phase difference phi because of that in R-L circuit current is out of phase.

 Dhiva said: (May 28, 2014) Generally is formula Xl=2piFL. So. frequency is increased.

 Brundha said: (Jan 19, 2015) To make the resistor voltage less than the inductor voltage? Normally we know the formula for frequency, xl = 2*3.14*l*f. So, the voltage across the inductor is increased.

 Shardul said: (Mar 8, 2015) Xl=2*3.14*f*l and Xc=1/2*3.14*f*c. So for in case of indicator its proportional form.

 Sanu Singh said: (Dec 7, 2015) But we have to inductive voltage more than resistance voltage so we have to decrease Xl.

 Surendra said: (Sep 9, 2016) XL = 2 * &phi * f * L. The frequency increase so the voltage across the inductor also increased.

 Saubhagya said: (Jan 9, 2017) I can't get this question. Anyone explain me clearly.

 Prasad Hajare said: (Sep 7, 2017) The frequency increase so the voltage across the inductor also increased. This one right conclusion.