Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 2)
2.
The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is
Discussion:
12 comments Page 1 of 2.
Prasad hajare said:
7 years ago
The frequency increase so the voltage across the inductor also increased. This one right conclusion.
Saubhagya said:
8 years ago
I can't get this question. Anyone explain me clearly.
Surendra said:
8 years ago
XL = 2 * &phi * f * L.
The frequency increase so the voltage across the inductor also increased.
The frequency increase so the voltage across the inductor also increased.
Sanu singh said:
9 years ago
But we have to inductive voltage more than resistance voltage so we have to decrease Xl.
Shardul said:
10 years ago
Xl=2*3.14*f*l and Xc=1/2*3.14*f*c. So for in case of indicator its proportional form.
Brundha said:
10 years ago
To make the resistor voltage less than the inductor voltage?
Normally we know the formula for frequency,
xl = 2*3.14*l*f.
So, the voltage across the inductor is increased.
Normally we know the formula for frequency,
xl = 2*3.14*l*f.
So, the voltage across the inductor is increased.
Dhiva said:
1 decade ago
Generally is formula Xl=2piFL.
So. frequency is increased.
So. frequency is increased.
Ganesh shind said:
1 decade ago
For resistive circuit voltage and current are in phase but for.
R-L circuit current lags the voltage by 90 degree so there is phase difference phi because of that in R-L circuit current is out of phase.
R-L circuit current lags the voltage by 90 degree so there is phase difference phi because of that in R-L circuit current is out of phase.
Danish baidar said:
1 decade ago
To make the resistor voltage less than the inductor voltage.
Inductor voltage has to be increased.
VL=I(2*pi*f*L)
So f is Increased to increase Inductor voltage.
Inductor voltage has to be increased.
VL=I(2*pi*f*L)
So f is Increased to increase Inductor voltage.
Kishore said:
1 decade ago
XL= 2*3.14*f*L
Here inductive reactance increases by increasing frequency, so the voltage across the inductor increases.
Here inductive reactance increases by increasing frequency, so the voltage across the inductor increases.
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