# Electrical Engineering - RL Circuits - Discussion

Discussion Forum : RL Circuits - General Questions (Q.No. 2)

2.

The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is

Discussion:

12 comments Page 1 of 2.
Prasad hajare said:
7 years ago

The frequency increase so the voltage across the inductor also increased. This one right conclusion.

Saubhagya said:
8 years ago

I can't get this question. Anyone explain me clearly.

Surendra said:
8 years ago

XL = 2 * &phi * f * L.

The frequency increase so the voltage across the inductor also increased.

The frequency increase so the voltage across the inductor also increased.

Sanu singh said:
9 years ago

But we have to inductive voltage more than resistance voltage so we have to decrease Xl.

Shardul said:
10 years ago

Xl=2*3.14*f*l and Xc=1/2*3.14*f*c. So for in case of indicator its proportional form.

Brundha said:
10 years ago

To make the resistor voltage less than the inductor voltage?

Normally we know the formula for frequency,

xl = 2*3.14*l*f.

So, the voltage across the inductor is increased.

Normally we know the formula for frequency,

xl = 2*3.14*l*f.

So, the voltage across the inductor is increased.

Dhiva said:
1 decade ago

Generally is formula Xl=2piFL.

So. frequency is increased.

So. frequency is increased.

Ganesh shind said:
1 decade ago

For resistive circuit voltage and current are in phase but for.

R-L circuit current lags the voltage by 90 degree so there is phase difference phi because of that in R-L circuit current is out of phase.

R-L circuit current lags the voltage by 90 degree so there is phase difference phi because of that in R-L circuit current is out of phase.

Danish baidar said:
1 decade ago

To make the resistor voltage less than the inductor voltage.

Inductor voltage has to be increased.

VL=I(2*pi*f*L)

So f is Increased to increase Inductor voltage.

Inductor voltage has to be increased.

VL=I(2*pi*f*L)

So f is Increased to increase Inductor voltage.

Kishore said:
1 decade ago

XL= 2*3.14*f*L

Here inductive reactance increases by increasing frequency, so the voltage across the inductor increases.

Here inductive reactance increases by increasing frequency, so the voltage across the inductor increases.

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