Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 3)
3.
In a series RL circuit, 12 V rms is measured across the resistor, and 14 V rms is measured across the inductor. The peak value of the source voltage is
Discussion:
15 comments Page 1 of 2.
Chaitanya said:
1 decade ago
Sqrt(VL^2+VR^2) = Vrms.
i.e sqrt 12^2+14^2 = sqrt 340.
Vp = sqrt 2*Vrms.
i.e Sqrt(2*340) = sqrt 680 = 26.0 V approx.
i.e sqrt 12^2+14^2 = sqrt 340.
Vp = sqrt 2*Vrms.
i.e Sqrt(2*340) = sqrt 680 = 26.0 V approx.
(1)
Samuel amu said:
1 decade ago
In a series circuit, current is constant. assume a unity current flowing in the cct., then XL=VL/I, nb I=1(assumed). XL=14/1=14
and R=VR/I=12. cct impedance Z=(R^2+XL^2)^(-2)
Z=(12^2+14^2)^(-2)=18.439
peak voltage: Vp=IZ
Vp=1x18.439
Vp=18.439 v
So answer is Option A.
and R=VR/I=12. cct impedance Z=(R^2+XL^2)^(-2)
Z=(12^2+14^2)^(-2)=18.439
peak voltage: Vp=IZ
Vp=1x18.439
Vp=18.439 v
So answer is Option A.
Chris said:
1 decade ago
Current can't be constant, its a AC signal. If so, Z(L) would be zero.
But option B isn't correct either cause RMS isn't the same as peak.
But option B isn't correct either cause RMS isn't the same as peak.
Gerald said:
1 decade ago
The relationship between peak and rms voltages is given as: Vrms = (Vpeak)/sqrt(2).
As a continuation to Samuel Amu's solution, his answer (18.439V) is still the rms value.
Transforming to peak value gives:
Vpeak = (Vrms)*sqrt(2) = 18.439*sqrt(2) = 26.07 Volts.
As a continuation to Samuel Amu's solution, his answer (18.439V) is still the rms value.
Transforming to peak value gives:
Vpeak = (Vrms)*sqrt(2) = 18.439*sqrt(2) = 26.07 Volts.
D.P.MISHRA said:
1 decade ago
Sqrt(VL^2+VR^2)=Vrms.
i.e sqrt12^2+14^2=sqrt340.
Vp=sqrt2*Vrms.
i.e Sqrt(2*340)=sqrt680=26.0V approx.
i.e sqrt12^2+14^2=sqrt340.
Vp=sqrt2*Vrms.
i.e Sqrt(2*340)=sqrt680=26.0V approx.
Pravin said:
1 decade ago
Consider,
Two voltage are connected in series so the two are addition so simple as this Que.
12+14 = 26.
Two voltage are connected in series so the two are addition so simple as this Que.
12+14 = 26.
Pavan said:
1 decade ago
While taking RL load the relation ship can not be said by sqrt 2 times then rms value. Because for RL circuit V can be measured by Laplace which never in terms of Sin it will be exponential in nature which rms is not 1/sqrt 2.
otherwise answer is taken w.r.t. fundamental formula:
V = (12^2+14^2)^0.5.
Satisfies all condition.
otherwise answer is taken w.r.t. fundamental formula:
V = (12^2+14^2)^0.5.
Satisfies all condition.
Ashoka.J said:
1 decade ago
In series circuit v = v1+v2.
So total volume is 12+14 = 26.
26/2 = 13.V, peak = 13*1.414 = 18.38 v.
So total volume is 12+14 = 26.
26/2 = 13.V, peak = 13*1.414 = 18.38 v.
Guesh berhe said:
1 decade ago
I am satisfied by this question.
Tejal said:
10 years ago
Two voltage are connected in series so the two are addition so simple as this question:
12+14 = 26.
But 12 and 14 are RMS values, n in Q? Asked peak value of source.
Thus peak values can be calculated from RMS values from the formula, which implies Vp = VRMS*2.
Answer is 36.7.
12+14 = 26.
But 12 and 14 are RMS values, n in Q? Asked peak value of source.
Thus peak values can be calculated from RMS values from the formula, which implies Vp = VRMS*2.
Answer is 36.7.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers