Discussion :: RL Circuits - General Questions (Q.No.3)
|Samuel Amu said: (Feb 23, 2012)|
|In a series circuit, current is constant. assume a unity current flowing in the cct., then XL=VL/I, nb I=1(assumed). XL=14/1=14
and R=VR/I=12. cct impedance Z=(R^2+XL^2)^(-2)
peak voltage: Vp=IZ
So answer is Option A.
|Chris said: (Mar 22, 2012)|
|Current can't be constant, its a AC signal. If so, Z(L) would be zero.
But option B isn't correct either cause RMS isn't the same as peak.
|Gerald said: (Aug 29, 2012)|
|The relationship between peak and rms voltages is given as: Vrms = (Vpeak)/sqrt(2).
As a continuation to Samuel Amu's solution, his answer (18.439V) is still the rms value.
Transforming to peak value gives:
Vpeak = (Vrms)*sqrt(2) = 18.439*sqrt(2) = 26.07 Volts.
|D.P.Mishra said: (Jan 15, 2013)|
i.e Sqrt(2*340)=sqrt680=26.0V approx.
|Pravin said: (Feb 17, 2014)|
Two voltage are connected in series so the two are addition so simple as this Que.
12+14 = 26.
|Pavan said: (Apr 15, 2014)|
|While taking RL load the relation ship can not be said by sqrt 2 times then rms value. Because for RL circuit V can be measured by Laplace which never in terms of Sin it will be exponential in nature which rms is not 1/sqrt 2.
otherwise answer is taken w.r.t. fundamental formula:
V = (12^2+14^2)^0.5.
Satisfies all condition.
|Ashoka.J said: (Jan 14, 2015)|
|In series circuit v = v1+v2.
So total volume is 12+14 = 26.
26/2 = 13.V, peak = 13*1.414 = 18.38 v.
|Chaitanya said: (Jul 7, 2015)|
|Sqrt(VL^2+VR^2) = Vrms.
i.e sqrt 12^2+14^2 = sqrt 340.
Vp = sqrt 2*Vrms.
i.e Sqrt(2*340) = sqrt 680 = 26.0 V approx.
|Guesh Berhe said: (Aug 11, 2015)|
|I am satisfied by this question.|
|Tejal said: (Oct 23, 2015)|
|Two voltage are connected in series so the two are addition so simple as this question:
12+14 = 26.
But 12 and 14 are RMS values, n in Q? Asked peak value of source.
Thus peak values can be calculated from RMS values from the formula, which implies Vp = VRMS*2.
Answer is 36.7.
|Khushbu said: (Jan 29, 2016)|
You should write srrt(2) instead of 2 answer is correct.
|Karuna said: (Apr 29, 2016)|
|Really, they asked the peak value. So, the answer is (12 + 14)1.414 = 36.764.|
|Asad said: (Sep 4, 2016)|
|V = sqrt(Vr2 + Vl2),
V = sqrt(12 pow 2 +14 pow 2),
V = sqrt 340,
V = 18.43,
Vpeak = 18.43 x 1.41,
Vpeak = 26 volts.
|Manish Sharma said: (Sep 1, 2018)|
|26.00v is the correct answer.|
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