Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 3)
                   
                                       
                                3.
In a series RL circuit, 12 V rms is measured across the resistor, and 14 V rms is measured across the inductor. The peak value of the source voltage is
 
                                    Discussion:
15 comments Page 1 of 2.
                
                        Yida said: 
                         
                        4 years ago
                
                The right explanation @Asad.
                
                        Manish sharma said: 
                         
                        7 years ago
                
                26.00v is the correct answer.
                
                        ASAD said: 
                         
                        9 years ago
                
                V = sqrt(Vr2 + Vl2),
V = sqrt(12 pow 2 +14 pow 2),
V = sqrt 340,
V = 18.43,
Vpeak = 18.43 x 1.41,
Vpeak = 26 volts.
                V = sqrt(12 pow 2 +14 pow 2),
V = sqrt 340,
V = 18.43,
Vpeak = 18.43 x 1.41,
Vpeak = 26 volts.
                        Karuna said: 
                         
                        10 years ago
                
                Really, they asked the peak value. So, the answer is (12 + 14)1.414 = 36.764.
                
                        Khushbu said: 
                         
                        10 years ago
                
                @Tejal. 
You should write srrt(2) instead of 2 answer is correct.
                You should write srrt(2) instead of 2 answer is correct.
                        Tejal said: 
                         
                        1 decade ago
                
                Two voltage are connected in series so the two are addition so simple as this question:
12+14 = 26.
But 12 and 14 are RMS values, n in Q? Asked peak value of source.
Thus peak values can be calculated from RMS values from the formula, which implies Vp = VRMS*2.
Answer is 36.7.
                12+14 = 26.
But 12 and 14 are RMS values, n in Q? Asked peak value of source.
Thus peak values can be calculated from RMS values from the formula, which implies Vp = VRMS*2.
Answer is 36.7.
                        Guesh berhe said: 
                         
                        1 decade ago
                
                I am satisfied by this question.
                
                        Chaitanya said: 
                         
                        1 decade ago
                
                Sqrt(VL^2+VR^2) = Vrms.
i.e sqrt 12^2+14^2 = sqrt 340.
Vp = sqrt 2*Vrms.
i.e Sqrt(2*340) = sqrt 680 = 26.0 V approx.
                i.e sqrt 12^2+14^2 = sqrt 340.
Vp = sqrt 2*Vrms.
i.e Sqrt(2*340) = sqrt 680 = 26.0 V approx.
                     (1)
                
            
                        Ashoka.J said: 
                         
                        1 decade ago
                
                In series circuit v = v1+v2. 
So total volume is 12+14 = 26.
26/2 = 13.V, peak = 13*1.414 = 18.38 v.
                So total volume is 12+14 = 26.
26/2 = 13.V, peak = 13*1.414 = 18.38 v.
                        Pavan said: 
                         
                        1 decade ago
                
                While taking RL load the relation ship can not be said by sqrt 2 times then rms value. Because for RL circuit V can be measured by Laplace which never in terms of Sin it will be exponential in nature which rms is not 1/sqrt 2.
otherwise answer is taken w.r.t. fundamental formula:
V = (12^2+14^2)^0.5.
Satisfies all condition.
                otherwise answer is taken w.r.t. fundamental formula:
V = (12^2+14^2)^0.5.
Satisfies all condition.
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