Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
Discussion:
51 comments Page 4 of 6.
Sohel Shaikh said:
6 years ago
Multiply the number and power is added in this question.
Danthala vijayalakshmi said:
4 years ago
Here, Numbers are multiplied & powers were added.
(2)
Khaja said:
1 decade ago
6*5 = 30.
10^3*10^5 = 10^(3+5) = 10^8.
30*10^8.
10^3*10^5 = 10^(3+5) = 10^8.
30*10^8.
Ela said:
1 decade ago
6*5 = 30.
10^3*10^5 = 10^(3+5) = 10^8.
30*10^8.
10^3*10^5 = 10^(3+5) = 10^8.
30*10^8.
Sanghamitra Samal said:
1 decade ago
(6*10^3)*(5*10^5).
10^3*10^5 = 10^8.
6*5 = 30.
10^3*10^5 = 10^8.
6*5 = 30.
Harshitha said:
10 years ago
(6*10^3)*(5*10^5)
= 6*5*(10^3+5).
= 30*10^8.
= 6*5*(10^3+5).
= 30*10^8.
(1)
Rameshbabu said:
1 decade ago
Thank you for easy understandable explanation.
Sumit kumar said:
1 decade ago
Add the power and then multiply the base term.
Ankit said:
10 years ago
a^m * b^n = a*b^m+n.
(6*5)*10^5+3 = 30*10^8.
(6*5)*10^5+3 = 30*10^8.
Katlakunta anil said:
2 years ago
(6×10^3)(5×10^5) = (6×5)(10^3+5) = 30 × 10^8.
(16)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers