Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
Discussion:
50 comments Page 4 of 5.
Ela said:
10 years ago
6*5 = 30.
10^3*10^5 = 10^(3+5) = 10^8.
30*10^8.
10^3*10^5 = 10^(3+5) = 10^8.
30*10^8.
Rajaneeesh said:
10 years ago
6*5 = 30.
5+3 = 8.
= 30*10^8.
5+3 = 8.
= 30*10^8.
Ankit said:
10 years ago
a^m * b^n = a*b^m+n.
(6*5)*10^5+3 = 30*10^8.
(6*5)*10^5+3 = 30*10^8.
Harshitha said:
10 years ago
(6*10^3)*(5*10^5)
= 6*5*(10^3+5).
= 30*10^8.
= 6*5*(10^3+5).
= 30*10^8.
(1)
Amarnaath said:
9 years ago
(6 * 10^3)*(5 * 10^5).
Values : 6*5 = 30(multiplication).
Powers : 5 + 3 = 8(adding).
Then the answer is (30 * 10^8).
Values : 6*5 = 30(multiplication).
Powers : 5 + 3 = 8(adding).
Then the answer is (30 * 10^8).
(3)
Vinotha said:
9 years ago
Thank you all for the explanation.
Anil kumar said:
9 years ago
It's easy to understand. Thank you @Ashik.
Edward suvo said:
9 years ago
Thanks to all for giving a clear explanation.
Suresh k said:
9 years ago
Thank you for explaining the answer and providing the good shortcut method.
(1)
Dhivya said:
9 years ago
Simply the number 5 & 6 are multiplied & the powers are added.
(2)
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