Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 15)
15.
Four 8 
speakers are connected in parallel to the output of an audio amplifier. If the maximum voltage to the speakers is 12 V, the amplifier must be able to deliver to the speakers
speakers are connected in parallel to the output of an audio amplifier. If the maximum voltage to the speakers is 12 V, the amplifier must be able to deliver to the speakersDiscussion:
6 comments Page 1 of 1.
Sumeet Pandey said:
1 decade ago
1/R = 1/8 + 1/8 + 1/8 + 1/8.
1/R = 4/8.
R = 8/4.
R = 2 ohm.
P (total) = (V*V)/R.
P (total) = (12*12)/2.
P (total) = 72 Watt.
Therefore, P = 72/4
P = 18 Watt(for each speaker).
1/R = 4/8.
R = 8/4.
R = 2 ohm.
P (total) = (V*V)/R.
P (total) = (12*12)/2.
P (total) = 72 Watt.
Therefore, P = 72/4
P = 18 Watt(for each speaker).
Jitendra said:
1 decade ago
Rt = 1/8+1/8+1/8+1/8.
Rt = 2 ohm.
I = 12/2 = 6 amp.
P = 6*12 = 72 watt.
Rt = 2 ohm.
I = 12/2 = 6 amp.
P = 6*12 = 72 watt.
Pavi said:
8 years ago
1/R=1/8+1/8+1/8+1/8.
R=2ohm,
I=V/R,
=12/2=6A.
P=I^2R.
=6 * 6 * 2 = 72W.
R=2ohm,
I=V/R,
=12/2=6A.
P=I^2R.
=6 * 6 * 2 = 72W.
Waseem said:
8 years ago
Please, give the detailed explanation of this questions.
Sushil said:
1 decade ago
Jitendra is right. Answer should be 72.
Pintu sahoo said:
8 years ago
72 is correct answer.
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