Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 15)
15.
Four 8 
speakers are connected in parallel to the output of an audio amplifier. If the maximum voltage to the speakers is 12 V, the amplifier must be able to deliver to the speakers
speakers are connected in parallel to the output of an audio amplifier. If the maximum voltage to the speakers is 12 V, the amplifier must be able to deliver to the speakersDiscussion:
6 comments Page 1 of 1.
Pintu sahoo said:
8 years ago
72 is correct answer.
Pavi said:
8 years ago
1/R=1/8+1/8+1/8+1/8.
R=2ohm,
I=V/R,
=12/2=6A.
P=I^2R.
=6 * 6 * 2 = 72W.
R=2ohm,
I=V/R,
=12/2=6A.
P=I^2R.
=6 * 6 * 2 = 72W.
Waseem said:
8 years ago
Please, give the detailed explanation of this questions.
Sushil said:
1 decade ago
Jitendra is right. Answer should be 72.
Sumeet Pandey said:
1 decade ago
1/R = 1/8 + 1/8 + 1/8 + 1/8.
1/R = 4/8.
R = 8/4.
R = 2 ohm.
P (total) = (V*V)/R.
P (total) = (12*12)/2.
P (total) = 72 Watt.
Therefore, P = 72/4
P = 18 Watt(for each speaker).
1/R = 4/8.
R = 8/4.
R = 2 ohm.
P (total) = (V*V)/R.
P (total) = (12*12)/2.
P (total) = 72 Watt.
Therefore, P = 72/4
P = 18 Watt(for each speaker).
Jitendra said:
1 decade ago
Rt = 1/8+1/8+1/8+1/8.
Rt = 2 ohm.
I = 12/2 = 6 amp.
P = 6*12 = 72 watt.
Rt = 2 ohm.
I = 12/2 = 6 amp.
P = 6*12 = 72 watt.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers