Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 15)
15.
Four 8 
speakers are connected in parallel to the output of an audio amplifier. If the maximum voltage to the speakers is 12 V, the amplifier must be able to deliver to the speakers
speakers are connected in parallel to the output of an audio amplifier. If the maximum voltage to the speakers is 12 V, the amplifier must be able to deliver to the speakersDiscussion:
6 comments Page 1 of 1.
Jitendra said:
1 decade ago
Rt = 1/8+1/8+1/8+1/8.
Rt = 2 ohm.
I = 12/2 = 6 amp.
P = 6*12 = 72 watt.
Rt = 2 ohm.
I = 12/2 = 6 amp.
P = 6*12 = 72 watt.
Sumeet Pandey said:
1 decade ago
1/R = 1/8 + 1/8 + 1/8 + 1/8.
1/R = 4/8.
R = 8/4.
R = 2 ohm.
P (total) = (V*V)/R.
P (total) = (12*12)/2.
P (total) = 72 Watt.
Therefore, P = 72/4
P = 18 Watt(for each speaker).
1/R = 4/8.
R = 8/4.
R = 2 ohm.
P (total) = (V*V)/R.
P (total) = (12*12)/2.
P (total) = 72 Watt.
Therefore, P = 72/4
P = 18 Watt(for each speaker).
Sushil said:
1 decade ago
Jitendra is right. Answer should be 72.
Waseem said:
8 years ago
Please, give the detailed explanation of this questions.
Pavi said:
8 years ago
1/R=1/8+1/8+1/8+1/8.
R=2ohm,
I=V/R,
=12/2=6A.
P=I^2R.
=6 * 6 * 2 = 72W.
R=2ohm,
I=V/R,
=12/2=6A.
P=I^2R.
=6 * 6 * 2 = 72W.
Pintu sahoo said:
8 years ago
72 is correct answer.
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