Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 8)
8.
Four equal-value resistors are connected in parallel. Ten volts are applied across the parallel circuit and 2 mA are measured from the source. The value of each resistor is
12.5 
200
20 K
50
Answer: Option
Explanation:
10/(R/4) = 2 mA
40/R = 2 mA
R = 40/2 mA
= 40/0.002 A
= 20000 kohm (20 kohm)
Discussion:
4 comments Page 1 of 1.
Majid Mahmood said:
6 years ago
So simple total current is 2mA and total four resistance is equal value so 2/4 = 0.5mA.
So each resistance current is 0.5mA.
And in parallel voltage is same so voltage is 10v.
R = v/i = 10/0.5 = 20kohm.
So each resistance current is 0.5mA.
And in parallel voltage is same so voltage is 10v.
R = v/i = 10/0.5 = 20kohm.
(1)
KARTHIK said:
1 decade ago
USE OHM'S LAW:
V/I = R/4.
(4*V/I) = R.
(4*10/2mA) = R.
R = 20 kohm.
V/I = R/4.
(4*V/I) = R.
(4*10/2mA) = R.
R = 20 kohm.
Mrakovic said:
1 decade ago
U = 10V.
I = 2mA = 0.002A.
R1 = R2 = R3 = R4 = Rn =?.
R = U/I = 10/0.002 = 5000 ohm.
R = Rn/n follow.
Rn = R*n = 5000*4 = 20000 ohm = 20k ohm.
I = 2mA = 0.002A.
R1 = R2 = R3 = R4 = Rn =?.
R = U/I = 10/0.002 = 5000 ohm.
R = Rn/n follow.
Rn = R*n = 5000*4 = 20000 ohm = 20k ohm.
Arundeep singh said:
1 decade ago
It can be explained in easy mode as 2 mA is total current so resistors are equal so 2/4= 0.5 mA in each and R = V/I.
10/ (0.5 x10 ^-3) = 20Kohm.
10/ (0.5 x10 ^-3) = 20Kohm.
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