# Electrical Engineering - Parallel Circuits - Discussion

### Discussion :: Parallel Circuits - General Questions (Q.No.8)

8.

Four equal-value resistors are connected in parallel. Ten volts are applied across the parallel circuit and 2 mA are measured from the source. The value of each resistor is

 [A]. 12.5 [B]. 200 [C]. 20 K [D]. 50

Explanation:

10/(R/4) = 2 mA

40/R = 2 mA

R = 40/2 mA

= 40/0.002 A

= 20000 kohm (20 kohm)

 Arundeep Singh said: (Jun 22, 2012) It can be explained in easy mode as 2 mA is total current so resistors are equal so 2/4= 0.5 mA in each and R = V/I. 10/ (0.5 x10 ^-3) = 20Kohm.

 Mrakovic said: (Sep 24, 2013) U = 10V. I = 2mA = 0.002A. R1 = R2 = R3 = R4 = Rn =?. R = U/I = 10/0.002 = 5000 ohm. R = Rn/n follow. Rn = R*n = 5000*4 = 20000 ohm = 20k ohm.

 Karthik said: (May 21, 2015) USE OHM'S LAW: V/I = R/4. (4*V/I) = R. (4*10/2mA) = R. R = 20 kohm.

 Majid Mahmood said: (Aug 24, 2019) So simple total current is 2mA and total four resistance is equal value so 2/4 = 0.5mA. So each resistance current is 0.5mA. And in parallel voltage is same so voltage is 10v. R = v/i = 10/0.5 = 20kohm.