Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385
38.5
3.1
31
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
102 comments Page 3 of 11.

K.Niranjan said:   1 decade ago
According to ohms law V=IR
r=v/i=110/3.5=31.42

Ujwala said:   1 decade ago
Ohms law V=IR.

Then R=V/I.

Given,

V=110v.

I=3.5A

Therfore R=110/3.5=31.428.

So the given answer is correct

Senthil Nathan.M said:   1 decade ago
Given
V=110V
I=3.5A

By Ohms law
V=IR
R=V/I
=110/3.5
=31.428
=31 Ohms

Gaurav said:   1 decade ago
Yes, Itis absolutly correct. Always remember formula
V=IR V....voltage
I....ampere
R...ohms

Swapna said:   1 decade ago
Its exactly correct. We have to remember this formula.

V=IR.

Saravanan.k said:   1 decade ago
Given
V=110V
I=3.5A

By Ohms law
V=IR
R=V/I
=110/3.5
=31.428
=31 Ohms

Manikandan. K said:   1 decade ago
Ohm's law cab be stated in workd as the current in a resistive circuit is directly proportional to its applied voltage and inversely proportional to its resistance.
Formulas are;
I=V/R or V=IR or R=V/I

Lakshman said:   1 decade ago
At constant temperature Current flowing through the conductor is directly proportional to the applied voltage.
Formula;
I=V/R

NILESH KUMAR SOLANKI said:   1 decade ago
according to ohms law
V=IR OR R=V/R
WE CAN PUT I=3.5 & V=110 THEN
R=110/3.5=31.4

Satish said:   1 decade ago
Its exactly correct. We have to remember this formula.
I=V/R or V=IR or R=V/I.


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