Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 11)
11.
A 6 V battery is connected to a 300 
load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?
load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?Discussion:
23 comments Page 1 of 3.
Aniket said:
1 decade ago
What is the relation between current and frequency?
Which is quantity that is measured in h?
Which is quantity that is measured in h?
Nithin said:
1 decade ago
Please reply to the above question.
Hawks_xavier said:
1 decade ago
Ans = 40/0.02(current through 300Ohms Load)
LKI said:
1 decade ago
P=VI
E=P*t
I=V/R=6/300=.02A
40=.02*t
t=40/.02=2000h
E=P*t
I=V/R=6/300=.02A
40=.02*t
t=40/.02=2000h
Md. Muin Uddin said:
1 decade ago
Energy produce by battery = 40*6 = 240whr
Power taken by load = v*v/r = 0.12
So current supplying time = 240/.12=2000hr.
Power taken by load = v*v/r = 0.12
So current supplying time = 240/.12=2000hr.
Chaitanya said:
1 decade ago
ih=40.
i=v/r
we knw v=6 n r=300
sub in 1st eqn we get h=2000
i=v/r
we knw v=6 n r=300
sub in 1st eqn we get h=2000
Phani bhargav.v said:
1 decade ago
Actually load may be or may not be estimate like this as 300 ohms, why because power consumption is depend upon their capacity in fact their wattage.
Upendra said:
1 decade ago
Actually current taken by 300ohm load is 6/300=0.02Amp. If condition saying,battery is under 40AH then to cover 40Amps, load has to take 2000hr at a constant current of 0.02Amps.
So answer is 'C'.
So answer is 'C'.
Ashraf said:
1 decade ago
Energy produce by battery = 40*6 = 240whr
Power taken by load = v*v/r = 0.12
So current supplying time = 240/.12=2000hr
Power taken by load = v*v/r = 0.12
So current supplying time = 240/.12=2000hr
Nick said:
1 decade ago
I=V/R=6/300=0.02A
T=40Ah/0.02A=2000h
T=40Ah/0.02A=2000h
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