Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 11)
11.
A 6 V battery is connected to a 300 
load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?
load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?Discussion:
23 comments Page 2 of 3.
Bhupendra kumar marwal said:
1 decade ago
The unit of load is not given therefore the load should actually be considered to be 300w in place of 300ohm.
T.T.ACHARYA said:
1 decade ago
The procedure is as follows:
=> ampere(A)xhour(T)=(voltage(V)/resistance(R))xhour(T)
=> 40 =(6/300) X T
=> T =(40X300)/6
=> T =2000h
=> ampere(A)xhour(T)=(voltage(V)/resistance(R))xhour(T)
=> 40 =(6/300) X T
=> T =(40X300)/6
=> T =2000h
Rajajee said:
1 decade ago
In the above problem given ah=40 and we get i from v=i*r as 0.02.
So in ah=40 amp a=0.02, So .02*h=40.
h=40/0.02=2000.
So in ah=40 amp a=0.02, So .02*h=40.
h=40/0.02=2000.
Shweta said:
1 decade ago
I = V/R.
= 6/300.
= 0.02A.
Ah = 40.
H = 40/A.
= 40/0.02.
= 2000.
= 6/300.
= 0.02A.
Ah = 40.
H = 40/A.
= 40/0.02.
= 2000.
(1)
Sabir said:
8 years ago
Energy E = V * Q = V * IT = 6 * 40 = 240WH.
POWER P=VI=Vsqr /R =.12W,
E = P * T,
T = E/P = 2k.
POWER P=VI=Vsqr /R =.12W,
E = P * T,
T = E/P = 2k.
Padma said:
8 years ago
Yes, you are Correct @Sabir.
Parth said:
8 years ago
I = V/R.
= 6/300,
= 0.02.
As we know it rates 40Ah, thus,
40 = I * t.
40 = 0.02 * t,
t = 40/0.02,
t = 2000 h.
= 6/300,
= 0.02.
As we know it rates 40Ah, thus,
40 = I * t.
40 = 0.02 * t,
t = 40/0.02,
t = 2000 h.
SIRKUDOS said:
8 years ago
First get the power consumed.
V=IR I = V/R =6/300 = 0.02A.
P = IV = 0.02*6=0.12W. That's is the load power.
To find the battery power.
P=IV 6*40 = 240Wh.
Then to find the hour the load will run.
240wh/0.12w = 2000h.
V=IR I = V/R =6/300 = 0.02A.
P = IV = 0.02*6=0.12W. That's is the load power.
To find the battery power.
P=IV 6*40 = 240Wh.
Then to find the hour the load will run.
240wh/0.12w = 2000h.
Suri said:
7 years ago
V=I x R.
6V=I x 300ohms.
I=6V / 300ohms.
I=0.02Amps.
40Amps-hour / 0.02Amps = 2000 hours.
2000 Hours Answer.
6V=I x 300ohms.
I=6V / 300ohms.
I=0.02Amps.
40Amps-hour / 0.02Amps = 2000 hours.
2000 Hours Answer.
Rajakumar said:
6 years ago
Current through load I=V/R.
I=6/300=0.02 then,
Rating=40AH,
40=0.02H.
So, Duration H=2000.
I=6/300=0.02 then,
Rating=40AH,
40=0.02H.
So, Duration H=2000.
(1)
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