Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 11)
11.
A 6 V battery is connected to a 300 
load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?
load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?Discussion:
23 comments Page 3 of 3.
HAris said:
6 years ago
Simply it can solve by this method:
It's given : Ah=40 so, h=40/A.
TO find A=?
I=V/R, = 6/300=0.02A. Now put in above 'h' eq.
h=40/A, = 40/0.02= 2000 hours.
It's given : Ah=40 so, h=40/A.
TO find A=?
I=V/R, = 6/300=0.02A. Now put in above 'h' eq.
h=40/A, = 40/0.02= 2000 hours.
(4)
Shahid said:
4 years ago
V/R =6/300 =0.02A
Load time = Battery Capacity in Ah/Load Current.
= 40Ah/.02A = 2000h.
Load time = Battery Capacity in Ah/Load Current.
= 40Ah/.02A = 2000h.
(7)
SASMITA MAHALIK said:
4 months ago
Simply it can solve by this method:.
It's given : Ah=40 so, h=40/A.
TO find A=?
I=V/R, = 6/300=0. 02A. Now put in above 'h' eq.
H=40/A, = 40/0.02 = 2000 hours.
It's given : Ah=40 so, h=40/A.
TO find A=?
I=V/R, = 6/300=0. 02A. Now put in above 'h' eq.
H=40/A, = 40/0.02 = 2000 hours.
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