Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 3)
3.
Find the total current through R3 in the given circuit.
Discussion:
41 comments Page 3 of 5.
Sanju said:
9 years ago
Let's consider a point of junction of r2 and r1 has a potential V2.
Then by KCL: ((24 - V2)/r1) = ((V2 - (-18))/r2) + ((V2 - (ground voltage 0V) )/ r3)
We get V2 = 3/38 volts,
and I through register is V2/r3 = 7.3 mA.
Then by KCL: ((24 - V2)/r1) = ((V2 - (-18))/r2) + ((V2 - (ground voltage 0V) )/ r3)
We get V2 = 3/38 volts,
and I through register is V2/r3 = 7.3 mA.
Nii AflorhTetteh said:
1 month ago
I think the answer is 0.8mA.
BHUSHAN R CHAUDHARI said:
1 decade ago
Mayur you are right, common point is 6 volt higher than ref. point i.e. voltage across 3.3kohm resister is 6v. therefore current through it is 6v/3.3kohm = 1.8mA.
Krishnan said:
1 decade ago
Can any one explain the answer more clearly?
M.V.KRISHNA/PALVONCHA said:
1 decade ago
You are right Beth Tate.
REDDI said:
1 decade ago
We apply the kirchoff current law
(V-24/1.2)+(V+18/1.2)+(V/3.3)=0
we get V=2.55Mv
I=V/R=(2.55/3.3)=0.77mA
(V-24/1.2)+(V+18/1.2)+(V/3.3)=0
we get V=2.55Mv
I=V/R=(2.55/3.3)=0.77mA
Adnan CECOSIAN said:
1 decade ago
Use mesh analysis:
Create two loops then apply KVL we get 2 equations
Loop1; (1.2k)(I1)+(1.2k)(I1+I2)=24
Loop2: (1.2k)(I2)+(1.2k)(I1+I2)=-18
Rearrange these two equations
then find Whole Deterimnent which i found
=4.32k^2
use cramer Rule
I1=18.35mA
and I2=16.6mA
now therefore current through 1.2kohm Resistor is
I1+I2=18.35-16.6
=1.75mA
So Answer D is correct.
Create two loops then apply KVL we get 2 equations
Loop1; (1.2k)(I1)+(1.2k)(I1+I2)=24
Loop2: (1.2k)(I2)+(1.2k)(I1+I2)=-18
Rearrange these two equations
then find Whole Deterimnent which i found
=4.32k^2
use cramer Rule
I1=18.35mA
and I2=16.6mA
now therefore current through 1.2kohm Resistor is
I1+I2=18.35-16.6
=1.75mA
So Answer D is correct.
Bettycroger said:
1 decade ago
The question asked for the current through R3 = 3.3kohm
Wee kian said:
1 decade ago
So is R2 or R3. the diagram is so misleading. does the VS1 connected to ground or just R3?
Pocahontas said:
1 decade ago
The answer that I've got is 0.769mA using the superposition theorem.
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