Electrical Engineering - Circuit Theorems and Conversions - Discussion

Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 3)
3.
Find the total current through R3 in the given circuit.

7.3 mA
5.5 mA
12.8 mA
1.8 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
40 comments Page 1 of 4.

Albert said:   3 years ago
Yes, @Stoyan.

0.769mA is my answer using mesh analysis.
(14)

Syed Zakeer said:   3 years ago
The answer is,

R3 = VS1-VS2*R3 = 1.8mA.
(5)

Calculuseuler said:   5 years ago
The 1.2k and the 18v source, are open leaving 24v source connected in series with the other two.

So, the current through 3.3k.
= 24/3.3,
=7.3mA.
(5)

Sivakumar.G said:   6 years ago
24-18 = 6v.

Total current through r3.
r3 = 3.3.

I = V/R.
I = 6/3.3.
I = 1.80.
(5)

Ronit said:   1 decade ago
The answer I'm getting is 0.77mA.

Can anyone explain it - How do they get the answer 1.8mA ?
(2)

Sikandar said:   6 years ago
No, the Correct ans is 5.3mA. So option B is correct.
(2)

Satyajit said:   8 years ago
The voltage across the 3300-ohm resistor is 2.538 v, not 6 volt due to drop in 1200 ohm resistors.
By nodal analysis, superposition theorem, Thevenin's theorem I got the answer 0.000769amp
(2)

Beth Tate said:   1 decade ago
If you do the node analysis on this problem, you get your current to be .769 mA. By splitting the above circuit into two sections with 2 diffferent currents, you also get .769 mA. How do you come to get the answer 1.8 mA ?
(1)

Egni said:   3 years ago
Please clarify at which point the lowest point of R3 connects it to the ground.
(1)

Anon said:   6 years ago
I don't agree with the 6V Vth since the circuit has aiding voltages.
(1)


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