Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 3)
3.
Find the total current through R3 in the given circuit.
Discussion:
40 comments Page 2 of 4.
Kiruthika said:
8 years ago
I also got the answer 0.769mA.
(1)
Bibek said:
7 years ago
@Mayur.
Can you help me by explaining how you have calculated Thevenin Voltage?
Can you help me by explaining how you have calculated Thevenin Voltage?
Basavaraj S Kumbalavati said:
9 years ago
From nodal analysis,
Node voltage is 2.538v.
Current through 3.3Kohm is (2.358/3.3) * mA = .769mA.
Node voltage is 2.538v.
Current through 3.3Kohm is (2.358/3.3) * mA = .769mA.
Swallah Marani said:
9 years ago
Using superposition.
Current produced by 24V = 11.5A
Current produced by 18V = 8.7A
Resultant current ; 11.5- 8.7 =2.8
Current in R3 3.3 ; 2.8[1.2]/[1.2+3.3] = 0.75A#.
Current produced by 24V = 11.5A
Current produced by 18V = 8.7A
Resultant current ; 11.5- 8.7 =2.8
Current in R3 3.3 ; 2.8[1.2]/[1.2+3.3] = 0.75A#.
Shivanya said:
9 years ago
By using source transformation we get .769 as an answer.
Raghukumar b s said:
9 years ago
24 - 18 = 6v.
Total current through r3.
r3 = 3.3k ohm.
I = V/R.
I = 6/3.3k ohm.
I = 1.80mA.
Total current through r3.
r3 = 3.3k ohm.
I = V/R.
I = 6/3.3k ohm.
I = 1.80mA.
Rituraj patra said:
8 years ago
The voltage across r3 is24-18 = 6, and current is 6/3.3=1.8.
Dev said:
8 years ago
I got 0.769 mA through 3.3 ohms resistor using KVL, node analysis, superposition according to my view answer is .769 mAmp.
Thanks.
Thanks.
Stoyan said:
8 years ago
The correct answer is 0.769 mA. I also agree.
Sanju said:
9 years ago
Let's consider a point of junction of r2 and r1 has a potential V2.
Then by KCL: ((24 - V2)/r1) = ((V2 - (-18))/r2) + ((V2 - (ground voltage 0V) )/ r3)
We get V2 = 3/38 volts,
and I through register is V2/r3 = 7.3 mA.
Then by KCL: ((24 - V2)/r1) = ((V2 - (-18))/r2) + ((V2 - (ground voltage 0V) )/ r3)
We get V2 = 3/38 volts,
and I through register is V2/r3 = 7.3 mA.
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