Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 3)
3.
Find the total current through R3 in the given circuit.
Discussion:
40 comments Page 2 of 4.
Anon said:
6 years ago
I don't agree with the 6V Vth since the circuit has aiding voltages.
(1)
Egni said:
3 years ago
Please clarify at which point the lowest point of R3 connects it to the ground.
(1)
Bibek said:
8 years ago
@Mayur.
Can you help me by explaining how you have calculated Thevenin Voltage?
Can you help me by explaining how you have calculated Thevenin Voltage?
Stoyan said:
8 years ago
The correct answer is 0.769 mA. I also agree.
Dev said:
8 years ago
I got 0.769 mA through 3.3 ohms resistor using KVL, node analysis, superposition according to my view answer is .769 mAmp.
Thanks.
Thanks.
Rituraj patra said:
8 years ago
The voltage across r3 is24-18 = 6, and current is 6/3.3=1.8.
Raghukumar b s said:
9 years ago
24 - 18 = 6v.
Total current through r3.
r3 = 3.3k ohm.
I = V/R.
I = 6/3.3k ohm.
I = 1.80mA.
Total current through r3.
r3 = 3.3k ohm.
I = V/R.
I = 6/3.3k ohm.
I = 1.80mA.
Shivanya said:
9 years ago
By using source transformation we get .769 as an answer.
Swallah Marani said:
9 years ago
Using superposition.
Current produced by 24V = 11.5A
Current produced by 18V = 8.7A
Resultant current ; 11.5- 8.7 =2.8
Current in R3 3.3 ; 2.8[1.2]/[1.2+3.3] = 0.75A#.
Current produced by 24V = 11.5A
Current produced by 18V = 8.7A
Resultant current ; 11.5- 8.7 =2.8
Current in R3 3.3 ; 2.8[1.2]/[1.2+3.3] = 0.75A#.
Basavaraj S Kumbalavati said:
9 years ago
From nodal analysis,
Node voltage is 2.538v.
Current through 3.3Kohm is (2.358/3.3) * mA = .769mA.
Node voltage is 2.538v.
Current through 3.3Kohm is (2.358/3.3) * mA = .769mA.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers