Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 3)
3.
Find the total current through R3 in the given circuit.
Discussion:
40 comments Page 2 of 4.
BHUSHAN R CHAUDHARI said:
1 decade ago
Mayur you are right, common point is 6 volt higher than ref. point i.e. voltage across 3.3kohm resister is 6v. therefore current through it is 6v/3.3kohm = 1.8mA.
Calculuseuler said:
5 years ago
The 1.2k and the 18v source, are open leaving 24v source connected in series with the other two.
So, the current through 3.3k.
= 24/3.3,
=7.3mA.
So, the current through 3.3k.
= 24/3.3,
=7.3mA.
(5)
Sathish said:
1 decade ago
If we consider the first loop there are two voltage sources then why do we consider only 24v source alone? Can anybody answer my question?
Dev said:
8 years ago
I got 0.769 mA through 3.3 ohms resistor using KVL, node analysis, superposition according to my view answer is .769 mAmp.
Thanks.
Thanks.
Mayur said:
1 decade ago
I used the Thevenin voltage theorem across 3.3 K ohm.
Vth = 3V and Zth = 600 ohm so by this I got answer as 0.78 mA.
Vth = 3V and Zth = 600 ohm so by this I got answer as 0.78 mA.
REDDI said:
1 decade ago
We apply the kirchoff current law
(V-24/1.2)+(V+18/1.2)+(V/3.3)=0
we get V=2.55Mv
I=V/R=(2.55/3.3)=0.77mA
(V-24/1.2)+(V+18/1.2)+(V/3.3)=0
we get V=2.55Mv
I=V/R=(2.55/3.3)=0.77mA
Sfgsgsdgfdg said:
1 decade ago
Oh, everyone R3 is not connected to ground since it does not have a dot. Instead R3 is connected to VS1.
Basavaraj S Kumbalavati said:
9 years ago
From nodal analysis,
Node voltage is 2.538v.
Current through 3.3Kohm is (2.358/3.3) * mA = .769mA.
Node voltage is 2.538v.
Current through 3.3Kohm is (2.358/3.3) * mA = .769mA.
Ronit said:
1 decade ago
The answer I'm getting is 0.77mA.
Can anyone explain it - How do they get the answer 1.8mA ?
Can anyone explain it - How do they get the answer 1.8mA ?
(2)
Raghukumar b s said:
9 years ago
24 - 18 = 6v.
Total current through r3.
r3 = 3.3k ohm.
I = V/R.
I = 6/3.3k ohm.
I = 1.80mA.
Total current through r3.
r3 = 3.3k ohm.
I = V/R.
I = 6/3.3k ohm.
I = 1.80mA.
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