Electrical Engineering - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 2)
2.
A capacitor and a resistor are connected in series to a sine wave generator. The frequency is set so that the capacitive reactance is equal to the resistance and, thus, an equal amount of voltage appears across each component. If the frequency is increased
Discussion:
16 comments Page 1 of 2.
Remya said:
1 decade ago
xc=1/2pifc
Siva naik said:
1 decade ago
if xc is increases then inversely frequency decreases.so that voltage across the capacitor is higher than that of voltage across the resistor
Suresh said:
1 decade ago
Xc=1/(2pi.f.c) It shows that the reactance of capacitor is dependent about frequency.
If frequency increased then the reactance will be decreased.
But the resistanse is independent about frequency.
I hope you will understand.
If frequency increased then the reactance will be decreased.
But the resistanse is independent about frequency.
I hope you will understand.
Xyz mishra said:
1 decade ago
Vr>Vc. Because with increase in frequency the valie of xc decreases. As xc decreases so the potential drop also decreses. On the other paryt the vr remains the same as resistior is independent of frequency. So vc<vr.
Priya said:
1 decade ago
Xc = 1/2πfc
Xc ∝ 1/f
As f increases , Xc decreases --> Vc decreases
But R is independent of frequency --> Vr remains the same.
Hence Vr > Vc
Xc ∝ 1/f
As f increases , Xc decreases --> Vc decreases
But R is independent of frequency --> Vr remains the same.
Hence Vr > Vc
Vaibhav said:
1 decade ago
We know Xc=1/2pifcf, and if frequency increases then reactance decreases
and thus resistive voltage is greater than capacitive voltage or the frequency does not depend upon resistance hance resistive voltage unaffected by increase frequency while capacitive voltage decreases as initial by increase in frequency.
and thus resistive voltage is greater than capacitive voltage or the frequency does not depend upon resistance hance resistive voltage unaffected by increase frequency while capacitive voltage decreases as initial by increase in frequency.
Sanat said:
1 decade ago
xc=1/2pi.f.c;
So if f increases then xc decreases. So voltage drop across the 'C' decreases.
So if f increases then xc decreases. So voltage drop across the 'C' decreases.
Sachchida nand maurya said:
1 decade ago
We know that Vc=i.Xc & Vr=i.R
Given that
Vc = Vr
So f is inversely proportional to Vc.
Vr>Vc
Given that
Vc = Vr
So f is inversely proportional to Vc.
Vr>Vc
Kaushal said:
1 decade ago
Vc=i.Xc & Vr=i.R.
Given that
As given in question Vc = Vr
So f is inversely proportional to Vc.
Vr>Vc.
Given that
As given in question Vc = Vr
So f is inversely proportional to Vc.
Vr>Vc.
Sam said:
1 decade ago
As we know fc=1/2pifc. So if frequency increases than vc will decrease.
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