Electrical Engineering - Capacitors - Discussion

Discussion Forum : Capacitors - General Questions (Q.No. 2)
2.
A capacitor and a resistor are connected in series to a sine wave generator. The frequency is set so that the capacitive reactance is equal to the resistance and, thus, an equal amount of voltage appears across each component. If the frequency is increased
VR > VC
VC > VR
VR = VC
VR and VC = 0
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Selvaguru said:   7 years ago
Frequency and capacitive reactance value are inversely proportional to each other, when fc increased reduces the value of Xc hence VR >Vc.

Fazl hamad said:   9 years ago
Dear fellows.

AS xc = 1/2 pi.f.c as f increases inversely xc decrease,

Also vc = i. xc as xc decreases so voltage across capacitor decreases.

Thus vr is greater than vc.

Sayali sawant said:   10 years ago
Capacitive reactance is inversely propotional to the frequency but resistance is independent from frequency. So resistance is more than capacitance. So answer is vr > vc.
(1)

Mike said:   1 decade ago
Plain English. Capacitors allow a change in voltage to pass through. If it's allowing a higher frequency to pass through then the voltage drop on the capacitor lowers.

K.jeevitha said:   1 decade ago
vc = i.xc and vr = i.r.

vc = vr.

So vr >vc.

AMARENDRA DASH said:   1 decade ago
From the ques Vr = Vc.

So IR = IXc.

Xc inver.proper to f,
As f increase Xc decrease resulting IXc decrease i.e Vc decrease.

Hence Vr > Vc. answer.

Sam said:   1 decade ago
As we know fc=1/2pifc. So if frequency increases than vc will decrease.

Kaushal said:   1 decade ago
Vc=i.Xc & Vr=i.R.

Given that
As given in question Vc = Vr
So f is inversely proportional to Vc.

Vr>Vc.

Sachchida nand maurya said:   1 decade ago
We know that Vc=i.Xc & Vr=i.R
Given that
Vc = Vr
So f is inversely proportional to Vc.

Vr>Vc

Sanat said:   1 decade ago
xc=1/2pi.f.c;

So if f increases then xc decreases. So voltage drop across the 'C' decreases.


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