Electrical Engineering - Branch, Loop and Node Analyses - Discussion
Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 14)
14.
What is the voltage drop across R3?
Discussion:
16 comments Page 1 of 2.
Ankitha said:
1 decade ago
How to solve the problem?
Krishna agarwal said:
1 decade ago
Dear @Ankitha first consider a voltage V at point b/w R1 R2 R3 and then apply KCL at that point and then solve it for V. Again for voltage across R3 subtract VS2 from V.
SKy NeT said:
1 decade ago
Can anyone tell me how to do this problem?
ELIAS said:
1 decade ago
By Kirchhoff's current law through nodal analysis.
Solution:
Consider the equation,
(VA-VS1/R1) + (VA/R2) + (VA-VS2/R3) = 0
Solution:
Consider the equation,
(VA-VS1/R1) + (VA/R2) + (VA-VS2/R3) = 0
Ashiwani said:
1 decade ago
Va = 4.18 then,
VR3 = 0.183v = 183mv.
VR3 = 0.183v = 183mv.
Bibhuti said:
1 decade ago
Please can any one describe it step by step?
Fairoz said:
1 decade ago
Super position theorem is very good one to solve this type of network. Because calculation gets very simple.
Pratik soni said:
1 decade ago
Please help me who to solving the type questions &describe it's steps?
ALI said:
1 decade ago
We consider the print between R1, R2 and R3 = VA.
VA-12/86+VA-0/37+VA-4/90 = 0.
(90*37)*VA-(90*37)*12+(86*90)*VA+(37*86)*VA-(37*86)*4/(37*90*86) = 0.
11966 VA-50024 = 0.
11966 VA = 50024.
VA = 4.18.
VA-12/86+VA-0/37+VA-4/90 = 0.
(90*37)*VA-(90*37)*12+(86*90)*VA+(37*86)*VA-(37*86)*4/(37*90*86) = 0.
11966 VA-50024 = 0.
11966 VA = 50024.
VA = 4.18.
Paul said:
10 years ago
I'm still not the wiser. Anyone help me?
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