Electrical Engineering - Branch, Loop and Node Analyses - Discussion
Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 14)
14.
What is the voltage drop across R3?


Discussion:
16 comments Page 2 of 2.
Nehal patel said:
10 years ago
r1 + r2 + r3 - (vs1 + vs2) = r3.
Bikram said:
9 years ago
I have a question. When we have to use +ve or -ve sign in KCL nodal analysis equation?
Somesh said:
9 years ago
For first loop:
12= 68i' + 37(i' + i")
12= 105 i' + 37 i" -----------------------1
For 2nd loop:
4= 90 i" + 37(i' + i")
4= 37 i' + 127 i" ----------------------------2
Solve equations 1 and 2 we get;
i' =114mA,
i" = 2mA,
Vr3 = i" X R,
Vr3 = 2mA X 90,
Vr3 = 180mV.
12= 68i' + 37(i' + i")
12= 105 i' + 37 i" -----------------------1
For 2nd loop:
4= 90 i" + 37(i' + i")
4= 37 i' + 127 i" ----------------------------2
Solve equations 1 and 2 we get;
i' =114mA,
i" = 2mA,
Vr3 = i" X R,
Vr3 = 2mA X 90,
Vr3 = 180mV.
(1)
Clex said:
8 years ago
VA.4.18 is right. Further, how can be extracted 180mv?
(1)
Nireeksha said:
7 years ago
Here, we can use 4-va/90.
Geeta H said:
3 years ago
Thanks for explaining @Somesh.
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