Electrical Engineering - Branch, Loop and Node Analyses - Discussion
Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 14)
14.
What is the voltage drop across R3?
Discussion:
16 comments Page 1 of 2.
Somesh said:
9 years ago
For first loop:
12= 68i' + 37(i' + i")
12= 105 i' + 37 i" -----------------------1
For 2nd loop:
4= 90 i" + 37(i' + i")
4= 37 i' + 127 i" ----------------------------2
Solve equations 1 and 2 we get;
i' =114mA,
i" = 2mA,
Vr3 = i" X R,
Vr3 = 2mA X 90,
Vr3 = 180mV.
12= 68i' + 37(i' + i")
12= 105 i' + 37 i" -----------------------1
For 2nd loop:
4= 90 i" + 37(i' + i")
4= 37 i' + 127 i" ----------------------------2
Solve equations 1 and 2 we get;
i' =114mA,
i" = 2mA,
Vr3 = i" X R,
Vr3 = 2mA X 90,
Vr3 = 180mV.
(1)
Clex said:
8 years ago
VA.4.18 is right. Further, how can be extracted 180mv?
(1)
Ankitha said:
1 decade ago
How to solve the problem?
Krishna agarwal said:
1 decade ago
Dear @Ankitha first consider a voltage V at point b/w R1 R2 R3 and then apply KCL at that point and then solve it for V. Again for voltage across R3 subtract VS2 from V.
SKy NeT said:
1 decade ago
Can anyone tell me how to do this problem?
ELIAS said:
1 decade ago
By Kirchhoff's current law through nodal analysis.
Solution:
Consider the equation,
(VA-VS1/R1) + (VA/R2) + (VA-VS2/R3) = 0
Solution:
Consider the equation,
(VA-VS1/R1) + (VA/R2) + (VA-VS2/R3) = 0
Ashiwani said:
1 decade ago
Va = 4.18 then,
VR3 = 0.183v = 183mv.
VR3 = 0.183v = 183mv.
Bibhuti said:
1 decade ago
Please can any one describe it step by step?
Fairoz said:
1 decade ago
Super position theorem is very good one to solve this type of network. Because calculation gets very simple.
Pratik soni said:
1 decade ago
Please help me who to solving the type questions &describe it's steps?
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