Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 18)
18.
A square wave has a period of 60
s. The first odd harmonic is

Discussion:
18 comments Page 1 of 2.
Abishake said:
1 decade ago
Please give me clarifications.
Sakshar said:
1 decade ago
Please solve it.
Abdul Wahab said:
1 decade ago
t=60us
f=1/t=1/60us=16.66kHz
1st odd harmonic is 3*f=50KHz
f=1/t=1/60us=16.66kHz
1st odd harmonic is 3*f=50KHz
RENUGA said:
1 decade ago
TIME=60us
f=1/t
=16.66
3 harmonics=3*16.66
=49.98~=50KHZ'
f=1/t
=16.66
3 harmonics=3*16.66
=49.98~=50KHZ'
Aya said:
1 decade ago
Why 3 ?
Anand aec(asansol engineering college) said:
1 decade ago
As harmonics start from 2wt, 3wt, 4wt, 5wt, ..So on. As we have to determine the 1st odd harmonic so we have to determine 3wt. Now 3*(1/60us) = 50kHz.
Raghav said:
9 years ago
What is the formula for second harmonic and so on?
Pankaj said:
9 years ago
Please define even and odd harmonics formulas.
Jagan said:
9 years ago
Just multiply with the frequency with 2nd 3rd 4th.
With frequency ex if ask 2 odd harmonic means take normal frequent and multiply= F * 2.
With frequency ex if ask 2 odd harmonic means take normal frequent and multiply= F * 2.
Moh said:
7 years ago
I am not understanding this. Please explain me.
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