Electrical Engineering - Alternating Current and Voltage - Discussion

Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 18)
18.
A square wave has a period of 60 s. The first odd harmonic is
5 kHz
50 kHz
500 kHz
33.33 kHz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
18 comments Page 1 of 2.

Moh said:   7 years ago
I am not understanding this. Please explain me.
(1)

Abhisek said:   5 years ago
Yes @Ruio.

6*(10^-6) , change 60us in hz.
f = 1/t=1/(60*10^-6) = (10^5)/6.
Then you will get 16666.66 Hz = 16.66 KHZ.
Now, For 1st odd harmonic = (3 * 16.66)KHZ = 50KHZ.
(1)

M.aqsam raza said:   5 years ago
TIME=60us.

f=1/t.
=16.66.

3 harmonics=3*16.66.
=49.98~=50KHZ'.
(1)

Sushma said:   6 years ago
If they ask 1st harmonic means you have to multiply f * 2 since harmonic starts from 2, 3, 4. If they mention odd or even then you have to take which is odd and even and multiply it.
(1)

Deinie said:   6 years ago
What is the formula for 1st harmonic, 2nd harmonic? Please tell me.
(1)

Anand aec(asansol engineering college) said:   1 decade ago
As harmonics start from 2wt, 3wt, 4wt, 5wt, ..So on. As we have to determine the 1st odd harmonic so we have to determine 3wt. Now 3*(1/60us) = 50kHz.

Raghav said:   9 years ago
What is the formula for second harmonic and so on?

Pankaj said:   9 years ago
Please define even and odd harmonics formulas.

Jagan said:   9 years ago
Just multiply with the frequency with 2nd 3rd 4th.

With frequency ex if ask 2 odd harmonic means take normal frequent and multiply= F * 2.

Abishake said:   1 decade ago
Please give me clarifications.


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