Electrical Engineering - Alternating Current and Voltage - Discussion

Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 4)
4.
To produce an 800 Hz sine wave, a four-pole generator must be operated at
200 rps
400 rps
800 rps
1,600 rps
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
24 comments Page 1 of 3.

Vinay said:   1 decade ago
BY USING FORMULA, n=120f/P
=120*800/4
=24000 rpm
=24000/60 rps
n=400 rps

Saran said:   1 decade ago
N=120f/p
N=(120*800)/4=24000 rpm

Speed in rps = 24000/60 = 400rps

Abhishek Tiwari said:   1 decade ago
N=2*f/p(in rps)
so, N=2*800/4
N=400 rps

Santosh said:   1 decade ago
N=RPM*pole/120
800=RPM*4/120
RPM=800*120/4
so RPM=24000
RPS=24000/60
RPS=400

Swapnil said:   1 decade ago
N=120F/P.

N=120*800/4.

N=24000.

To convert it into rps.

24000/60 = 400.

Sai said:   1 decade ago
N = 120f/p.

= 120*800/4.

= 120*200.

= 24000 rpm.

= 24000/60 rps.

= 400.

Akshaya said:   1 decade ago
Every engineer has different creative. It is shown here.

You said:   1 decade ago
All showed same formula but differed in arrangement.

Dino said:   1 decade ago
Frequency = No of poles x Revolution Rate.
f = (2 * 400 rps).
f = 800 hz.

Asha.rrrrr said:   1 decade ago
What is the 60 here?


Post your comments here:

Your comments will be displayed after verification.