Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 25)
25.
The average half-cycle value of a sine wave with a 40 V peak is
Discussion:
12 comments Page 1 of 2.
Kuldeep said:
1 decade ago
@siba.
25.48 not wrong. Becuse always average value taken for half cycle. For complete cycle its value zero.
25.48 not wrong. Becuse always average value taken for half cycle. For complete cycle its value zero.
(2)
Threza said:
1 decade ago
Vavg = Vp x 0.637
= 40 x 0.637
= 25.48 V
= 40 x 0.637
= 25.48 V
(1)
Moumita said:
1 decade ago
Vavg = (2*Vm)/pi.
= (2*40)/3.14.
= 25.48.
= (2*40)/3.14.
= 25.48.
(1)
Pradeep jaiswal said:
1 decade ago
Integrate 40 sin t = 0, pi.
We get 2*40 = 80 then divide by pi.
We get 25.48 = ans.
We get 2*40 = 80 then divide by pi.
We get 25.48 = ans.
(1)
Kayum said:
10 years ago
Eav = 0.637*E.
(1)
Aabidha said:
7 years ago
I am not getting your answer clearly @Pradeep Jaiswal.
Please explain me in detail.
Please explain me in detail.
(1)
MADHU said:
5 years ago
v = 40 * sinwt.
Vavg = (1/π) * integral(sinwt) , wt from 0 toπ. (Half wave)
Vavg = 40/π * [cos(0) - cos(pi)]
Vavg = 80/π
Vavg = 25.47v.
Vavg = (1/π) * integral(sinwt) , wt from 0 toπ. (Half wave)
Vavg = 40/π * [cos(0) - cos(pi)]
Vavg = 80/π
Vavg = 25.47v.
(1)
Adeel said:
1 decade ago
Average Half Cycle Value = 2V / pi
= 2 * 40 / 3.14
= 25.48
= 2 * 40 / 3.14
= 25.48
Prasanthi said:
1 decade ago
avg = 0.637 * peak value
Siba said:
1 decade ago
Your answer is wrong
Correct answer 14.14
Peak value = v*ROOT2
V=(PV/ROOT 2)/2
Correct answer 14.14
Peak value = v*ROOT2
V=(PV/ROOT 2)/2
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers