Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 25)
25.
The average half-cycle value of a sine wave with a 40 V peak is
Discussion:
12 comments Page 1 of 2.
MADHU said:
5 years ago
v = 40 * sinwt.
Vavg = (1/π) * integral(sinwt) , wt from 0 toπ. (Half wave)
Vavg = 40/π * [cos(0) - cos(pi)]
Vavg = 80/π
Vavg = 25.47v.
Vavg = (1/π) * integral(sinwt) , wt from 0 toπ. (Half wave)
Vavg = 40/π * [cos(0) - cos(pi)]
Vavg = 80/π
Vavg = 25.47v.
(1)
Pratik wadekar said:
5 years ago
Thank you @Prasanthi.
Arshad said:
7 years ago
For Sine Half wave value should be= Vp/π
For Sine Full Wave its value becomes= 2 Vp/π.
For Sine Full Wave its value becomes= 2 Vp/π.
Aabidha said:
7 years ago
I am not getting your answer clearly @Pradeep Jaiswal.
Please explain me in detail.
Please explain me in detail.
(1)
Kayum said:
10 years ago
Eav = 0.637*E.
(1)
Pradeep jaiswal said:
1 decade ago
Integrate 40 sin t = 0, pi.
We get 2*40 = 80 then divide by pi.
We get 25.48 = ans.
We get 2*40 = 80 then divide by pi.
We get 25.48 = ans.
(1)
Moumita said:
1 decade ago
Vavg = (2*Vm)/pi.
= (2*40)/3.14.
= 25.48.
= (2*40)/3.14.
= 25.48.
(1)
Kuldeep said:
1 decade ago
@siba.
25.48 not wrong. Becuse always average value taken for half cycle. For complete cycle its value zero.
25.48 not wrong. Becuse always average value taken for half cycle. For complete cycle its value zero.
(2)
Threza said:
1 decade ago
Vavg = Vp x 0.637
= 40 x 0.637
= 25.48 V
= 40 x 0.637
= 25.48 V
(1)
Siba said:
1 decade ago
Your answer is wrong
Correct answer 14.14
Peak value = v*ROOT2
V=(PV/ROOT 2)/2
Correct answer 14.14
Peak value = v*ROOT2
V=(PV/ROOT 2)/2
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers