Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 13)
13.
The average value of a 12 V peak sine wave over one complete cycle is
Discussion:
18 comments Page 2 of 2.
RN BIRLA said:
1 decade ago
The Average value is defined the half cycle of sine wave that mean positive and negative. Therefore the value will be zero.
Mufid makrani said:
1 decade ago
Average value in case of sine wave is given by:
V = (Vp/period of conduction)*sin wt
= (12/2*pi)*sin (2*pi)
= (12/2*3.14)*sin (2*180)
=(12/6.28)*(0)
=0
since sin (n*pi) is always zero..
this expression is generally used for calculating average voltages in case of rectifiers.
V = (Vp/period of conduction)*sin wt
= (12/2*pi)*sin (2*pi)
= (12/2*3.14)*sin (2*180)
=(12/6.28)*(0)
=0
since sin (n*pi) is always zero..
this expression is generally used for calculating average voltages in case of rectifiers.
Mufidmakrani said:
1 decade ago
Average value = (1/period of conduction)*Vp*sinwt
=(1/2pi)*12*sin(2*pi)
=0
because sin (n*pi) is alwayz equals to zero
here (wt) is also the perios of conduction here one complete cycle means 2*pi= 360 in degree
=(1/2pi)*12*sin(2*pi)
=0
because sin (n*pi) is alwayz equals to zero
here (wt) is also the perios of conduction here one complete cycle means 2*pi= 360 in degree
Debashree said:
1 decade ago
Average value is always calculated for half of the cycle. In this case, full complete cycle, average value will be 0.
Trone said:
1 decade ago
But why we didn't used the "avg value = 0. 637 * peak" ?
Shailaja said:
1 decade ago
Ya balu is correct.
Santhi said:
1 decade ago
Avg value = 0.637 * peak
= 0.637 * 12
=7.64v
= 0.637 * 12
=7.64v
Balu hyderabad said:
1 decade ago
Sin wave have both positive and nagetive peaks. So the average value is 0.
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