Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 13)
13.
The average value of a 12 V peak sine wave over one complete cycle is
Discussion:
18 comments Page 1 of 2.
Sunil Malappuram said:
9 years ago
Average value over complete sine cycle is always zero.
(1)
Aniket said:
1 decade ago
It's so simple. As it's told here that peak value is 12 V over the entire sine wave and there are two halves of sine wave. One is positive half and another is negative half. So, the peak value of positive half would be 12 V and the peak value of negative half would be -12 V. Now if we go for evaluating the average value then we have to calculate in the following way: 12 + (-12)/2 i.e; equal to 0 (zero).
Venkat said:
8 years ago
Good explanation, Thanks.
Dinesh said:
8 years ago
Average value only calculated for half cycles only. If consider for the full cycle the positive and negative values nullify with each other and resultant becomes zero.
BALAN said:
8 years ago
Average value of sine wave over complete one cycle is V = 2*v(peak value)/3.14.
Rishabh modi said:
10 years ago
For 1 complete cycle of average voltage v = 2*v(peak value)/3.16.
Santosh said:
10 years ago
Start from 0 then max peak +12v to 0 it is half cycle.
Then start from 0 to peak -12v to 0 it is complete one cycle.
Then start from 0 to peak -12v to 0 it is complete one cycle.
Sarao said:
10 years ago
Please explain me average value.
Vikas said:
1 decade ago
Average value means DC value. In the sine wave there is no average value, therefore the average value is ZERO.
Balu hyderabad said:
1 decade ago
Sin wave have both positive and nagetive peaks. So the average value is 0.
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