Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 13)
13.
The average value of a 12 V peak sine wave over one complete cycle is
Discussion:
18 comments Page 1 of 2.
Balu hyderabad said:
1 decade ago
Sin wave have both positive and nagetive peaks. So the average value is 0.
Santhi said:
1 decade ago
Avg value = 0.637 * peak
= 0.637 * 12
=7.64v
= 0.637 * 12
=7.64v
Shailaja said:
1 decade ago
Ya balu is correct.
Trone said:
1 decade ago
But why we didn't used the "avg value = 0. 637 * peak" ?
Debashree said:
1 decade ago
Average value is always calculated for half of the cycle. In this case, full complete cycle, average value will be 0.
Mufidmakrani said:
1 decade ago
Average value = (1/period of conduction)*Vp*sinwt
=(1/2pi)*12*sin(2*pi)
=0
because sin (n*pi) is alwayz equals to zero
here (wt) is also the perios of conduction here one complete cycle means 2*pi= 360 in degree
=(1/2pi)*12*sin(2*pi)
=0
because sin (n*pi) is alwayz equals to zero
here (wt) is also the perios of conduction here one complete cycle means 2*pi= 360 in degree
Mufid makrani said:
1 decade ago
Average value in case of sine wave is given by:
V = (Vp/period of conduction)*sin wt
= (12/2*pi)*sin (2*pi)
= (12/2*3.14)*sin (2*180)
=(12/6.28)*(0)
=0
since sin (n*pi) is always zero..
this expression is generally used for calculating average voltages in case of rectifiers.
V = (Vp/period of conduction)*sin wt
= (12/2*pi)*sin (2*pi)
= (12/2*3.14)*sin (2*180)
=(12/6.28)*(0)
=0
since sin (n*pi) is always zero..
this expression is generally used for calculating average voltages in case of rectifiers.
RN BIRLA said:
1 decade ago
The Average value is defined the half cycle of sine wave that mean positive and negative. Therefore the value will be zero.
Cisel Xenyo Atsu said:
1 decade ago
The sine wave has the same values for both positive and negative cycles hence the average is equal to zero.
Aniket said:
1 decade ago
It's so simple. As it's told here that peak value is 12 V over the entire sine wave and there are two halves of sine wave. One is positive half and another is negative half. So, the peak value of positive half would be 12 V and the peak value of negative half would be -12 V. Now if we go for evaluating the average value then we have to calculate in the following way: 12 + (-12)/2 i.e; equal to 0 (zero).
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