Digital Electronics - Multivibrators and 555 Timer - Discussion
Discussion Forum : Multivibrators and 555 Timer - General Questions (Q.No. 4)
4.
A 22-k
resistor and a 0.02-
F capacitor are connected in series to a 5-V source. How long will it take the capacitor to charge to 3.4 V?


Discussion:
13 comments Page 1 of 2.
Sujats said:
1 decade ago
I want to know how to solve this problem or formula for it.
Sakshi said:
1 decade ago
What is the formula to solve this problem.
Korsa taressa said:
1 decade ago
How the answer be 0.501 ms?
Shafeeq said:
1 decade ago
Use this formula V=Vm(1-exp(-t/R*C))
Here all values are given and solve for t.
Here all values are given and solve for t.
Arvind said:
1 decade ago
What is other formula without calculator for exam?
Ambree said:
1 decade ago
Wt is the formula to calculate with out calculator ?
Vikas Kaushik said:
1 decade ago
V = Vo [ {exp(-t/RC) }- 1]
where
V = voltage across capacitor at any time t
Vo = supply voltage
where
V = voltage across capacitor at any time t
Vo = supply voltage
K.K said:
1 decade ago
The charging of capacitor is calculated.
T= ln(3) *RC.
T= ln(3) *RC.
Viendong194 said:
1 decade ago
Yes. this is a monostable that made by IC555.
When Vc=2/3Vo , T=ln(3)*RC.
When Vc=2/3Vo , T=ln(3)*RC.
Mohit Sharma said:
1 decade ago
V(c) = V(s)[1-e((-t)/RC)].
3.4 = 5[1-e((-t)/RC)].
3.4/5 = [1-e((-t)/RC)].
0.68 = 1-e((-t)/RC).
e((-t)/RC) = 0.32.
Taking natural log both sides, we have
-t/RC = -1.139.
t = 1.139 * 0.02u * 22K.
t = 0.501ms.
3.4 = 5[1-e((-t)/RC)].
3.4/5 = [1-e((-t)/RC)].
0.68 = 1-e((-t)/RC).
e((-t)/RC) = 0.32.
Taking natural log both sides, we have
-t/RC = -1.139.
t = 1.139 * 0.02u * 22K.
t = 0.501ms.
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