### Discussion :: Multivibrators and 555 Timer - General Questions (Q.No.4)

Sujats said: (May 2, 2011) | |

I want to know how to solve this problem or formula for it. |

Sakshi said: (May 6, 2011) | |

What is the formula to solve this problem. |

Korsa Taressa said: (May 13, 2011) | |

How the answer be 0.501 ms? |

Shafeeq said: (Jul 2, 2011) | |

Use this formula V=Vm(1-exp(-t/R*C)) Here all values are given and solve for t. |

Arvind said: (Aug 6, 2011) | |

What is other formula without calculator for exam? |

Ambree said: (Oct 1, 2011) | |

Wt is the formula to calculate with out calculator ? |

Vikas Kaushik said: (Jan 10, 2012) | |

V = Vo [ {exp(-t/RC) }- 1] where V = voltage across capacitor at any time t Vo = supply voltage |

K.K said: (May 8, 2013) | |

The charging of capacitor is calculated. T= ln(3) *RC. |

Viendong194 said: (Feb 16, 2014) | |

Yes. this is a monostable that made by IC555. When Vc=2/3Vo , T=ln(3)*RC. |

Mohit Sharma said: (Nov 4, 2014) | |

V(c) = V(s)[1-e((-t)/RC)]. 3.4 = 5[1-e((-t)/RC)]. 3.4/5 = [1-e((-t)/RC)]. 0.68 = 1-e((-t)/RC). e((-t)/RC) = 0.32. Taking natural log both sides, we have -t/RC = -1.139. t = 1.139 * 0.02u * 22K. t = 0.501ms. |

Aimal said: (Dec 17, 2014) | |

t = RC*ln(Vc/Vs). |

Uday Pratap Singh said: (Oct 20, 2016) | |

Voltage across capacitor is, Vc = V (1 - e^(-t/RC)). From question Vc = 3.4V, V = 5V, RC = 0.44 x 10^-3. Putting these values in above equation. 3.4 = 5 (1 - e^(-t/(0.44 * 10^(-3)))). After solving this equation, t = 0.501 ms. |

Harini said: (Feb 19, 2020) | |

How this problem is solved. Are said a formula for this problem. |

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