Digital Electronics - Memory and Storage - Discussion

Discussion Forum : Memory and Storage - General Questions (Q.No. 1)
1.
How many address bits are needed to select all memory locations in the 2118 16K × 1 RAM?
8
10
14
16
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
21 comments Page 2 of 3.

Chandu said:   5 years ago
It refers to Intel family model number.

Aniket jhala said:   4 years ago
What about 2118? Explain in detail.

Sri said:   1 decade ago
How to factorising 16384 by 2?

Dhanaji said:   9 years ago
Sir but how to use this 10+4.

Ravi said:   1 decade ago
1024 bits is equal to the 1 k

Ravikiran said:   1 decade ago
Why did you use 1024 as 1 K?

Abshir abdirizak said:   9 years ago
The answer is 10 + 4 = 14.

S Singh said:   8 years ago
What is mean by 2118?

Keshava said:   7 years ago
What is mean by 2118?

Nandhini said:   1 decade ago
Why did you use 1024?


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