Digital Electronics - Memory and Storage - Discussion
Discussion Forum : Memory and Storage - General Questions (Q.No. 1)
1.
How many address bits are needed to select all memory locations in the 2118 16K × 1 RAM?
Discussion:
21 comments Page 1 of 3.
Adarsh said:
2 months ago
what is meant by 2218?
@All.
it is just the model number of the given RAM, you need to check the chip size they have given it is 16k x 1.
Hence, we know that chip size is equal to a multiple of the depth size of the chip (16k) and the width of the chip (1bit).
Hence it is equal to 16k only, we know that 2^n, where n is the number of address lines used, 16k (16*1024) can be written as (2^4) + (2^10) after solving we get 2^ (4+10) equals to 2^14 after refer this to 2^n we get the n=14 as the answer.
@All.
it is just the model number of the given RAM, you need to check the chip size they have given it is 16k x 1.
Hence, we know that chip size is equal to a multiple of the depth size of the chip (16k) and the width of the chip (1bit).
Hence it is equal to 16k only, we know that 2^n, where n is the number of address lines used, 16k (16*1024) can be written as (2^4) + (2^10) after solving we get 2^ (4+10) equals to 2^14 after refer this to 2^n we get the n=14 as the answer.
Rudra prasad patra said:
2 years ago
How is it?
Anybody, Please explain in detail.
Anybody, Please explain in detail.
Aniket jhala said:
4 years ago
What about 2118? Explain in detail.
Chandu said:
5 years ago
It refers to Intel family model number.
Keshava said:
7 years ago
What is mean by 2118?
S Singh said:
8 years ago
What is mean by 2118?
Ajaj Ahmad said:
8 years ago
According to me, 10 is the right option.
Vaishnavi atram said:
9 years ago
Ram is only 2gb.
How to increase the RAM?
How to increase the RAM?
Abshir abdirizak said:
9 years ago
The answer is 10 + 4 = 14.
Dhanaji said:
9 years ago
Sir but how to use this 10+4.
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