Digital Electronics - Logic Gates - Discussion
Discussion Forum : Logic Gates - Filling the Blanks (Q.No. 1)
1.
The gates in this figure are implemented using TTL logic. If the input of the inverter is open, and you apply logic pulses to point B, the output of the AND gate will be ________.
Discussion:
7 comments Page 1 of 1.
Priya said:
8 years ago
Floating input of TTL is 1 always. So O/p of the NOT gate is I and B=1. But due to AND gate o/p becomes 0.
Appu said:
9 years ago
Pulses is correct one.
Appu said:
9 years ago
Answer is correct because. TTL is of negative logic so the input at inverter is open means it's high the output will be low so the and gate output is steady low.
HARSHA said:
1 decade ago
If A is open it mean input to the inverter is 0 so the o/p will be 1. Which is applied to the AND gate input. So the o/p will be the pulses applied on B.
Nandi said:
1 decade ago
If A is open then o/p at inverter will be 0 (low) i.e. ground; So the o/p after and gate will be low only.
Sachin Dohre said:
1 decade ago
If A is open means undefined so output must be undefined level.
Gopi said:
1 decade ago
It is a wrong answer because 1*pulses gives the pulses output.
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